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3 years ago

Please answer asap don’t troll!!!

Mathematics

1 answer:

zubka84 [21]3 years ago

8 0

you will do as you said yes yes i is fine with me but i’m going on the right now so bye bye u it was correct that

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In 2012, the population of a city was 6.27 million. The exponential growth rate was 1.47% per year.

Tcecarenko [31]

Answer:

a) $a(t)= 6.27e^{0.0147*t}$

b) 6.84 million

c) 2028.52

d) 47 years

Step-by-step explanation:

a)Here we know standard exponential growth rate is

$a(t)= ae^{k*t}$

In this put t=0 and a(t)=6.27 million

thus we get a = 6.27 million

now $\frac{da}{dt}=a(t)k$

this is equal to(in 2012)= $\frac{1.47}{100}*=0.0147$

b)Put t = 6

we get

$a(t)= 6.27e^{0.0147*6}$

=6.84 million

c) $8 = 6.27e^{0.0147*t}$

take log both sides

we get 16.52 years

d) $2*6.27=6.27e^{0.0147*t}$

take log both sides we get 47 years to get double the current population.

3 0

3 years ago

Suppose the function f(x) = 0.035x represents the number of U.S. dollars equivalent to x Russian rubles, and the function g(x) =

const2013 [10]

Answer:

g(f(x)) = 3.15x

Step-by-step explanation:

To find the number of Japanese yen equivalent to x russian rubles, we need to put one function into another.

If we take f(x) and put in into g(x), we will get Japanese yen in terms of rubles. Thus,

g(f(x)) = 90 (0.035x)

g(f(x)) = 3.15x

THis is the composite function which represents the number of Japanese yen equivalent to x Russian Rubles.

4 0

3 years ago

a car needw fixing and abe can fix it for $70 per hour with a $130 part, but gabe can fix it for $80 an hour with a $40 part. ho

Zolol [24]

70 + 130 = 200
This would be Abe’s one hour of work and the part
80 + 80 + 40 = 200
This would be Gabe’s two hours of work and the part

6 0

3 years ago

Read 2 more answers

H/5 = 5.1 What is H?

inysia [295]

This basically says all the steps ! If you have any questions just tell me :)

5 0

3 years ago

Read 2 more answers

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

6 0

3 years ago