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ozzi
3 years ago
11

Light-rail systems have been tried all over the country, and they've failed. Although the people who support them have noble int

entions, sadly, the system the city proposes is doomed to fail as well. People simply enjoy their cars too much to endure any inconvenience for the sake of the environment. And I don't blame them. As the owner of Jake's Used Cars and Trucks, I have seen the joy and freedom car ownership brings people. Americans will never abandon that feeling for the sake of being slightly better citizens. I believe it is far more responsible to purchase a high-quality car with good fuel efficiency. Building an entire light-rail system from the ground up, as the city proposes to do, will be more wasteful in the end if nobody uses it — not to mention that it will take years to build and cost taxpayers millions of dollars. I encourage all city residents to vote against the light-rail system on May 1. Which statement best describes the author's point of view? A. The author thinks Americans should be more environmentally responsible. B. The author wants citizens to visit his car dealership. C. The author is opposed to the light-rail project. D. The author would like the city to implement its project successfully.
Physics
2 answers:
Vesna [10]3 years ago
8 0
Citizens should vote against the proposed claim.
lisov135 [29]3 years ago
3 0

ANSWER: C. The author is opposed to the light-rail project.

EXPLANATION: The author understands the mentality and the sentiments of Americans. He knows the fact very well that people would never compromise their comfort, joy and freedom to become a good citizen. The author thinks they can be rather advised to buy high quality cars with good fuel efficiency than using the light rail system. So, to avoid taxpayers' millions of dollars, he wants the citizens to vote against it.

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PHYSICS<br> I need help with number two!!!!
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Answer:

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

Explanation:

Initial total energy = final total energy

PE₁ + KE₁ = PE₂ + KE₂

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

7 0
3 years ago
A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

Recall the equation for angular momentum:

L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

I_m = moment of inertia of the merry-go-round (kgm²)

\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

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L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

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2 years ago
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PV =NkT

Where,

N = Number of molecules

k = Boltzmann constant

V = Volume

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Our values are given as,

N = 1

k = 1.38*10^{-23}J/K

T = 27\°C = 27\°C + 273 = 300K

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Rearrange the equation to find V we have,

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