Newton's 2nd law of motion says
Net force = (mass) x (acceleration)
Plug in the things you know, and you have
80 N = (20 kg) x (acceleration)
Divide each side by (20 kg) :
80N / 20kg = acceleration
acceleration = 4 m/s²
Answer:
The horizontal component of the velocity vector is;
vh = 34.4 ft/s
The vertical component of the velocity vector is;
vy = 49.1 ft/s
Explanation:
Given;
Velocity of football v = 60 ft/s
Angle of elevation ∅ = 55°
The horizontal component of the velocity vector is;
vh = vcos∅
Substituting the values;
vh = 60cos55°
vh = 34.41458618106 ft/s
vh = 34.4 ft/s
The vertical component of the velocity vector is;
vy = vsin∅
Substituting the values;
vy = 60sin55°
vy = 49.14912265733 ft/s
vy = 49.1 ft/s
Answer:
The corresponding dimensions will be "x = 300 & y = 60".
Explanation:
Available fencing = 600 ft
Fencing,
⇒ 
⇒ 
As we know,
⇒ 
On substituting the given values, we get
...(equation 1)
On differentiating with respect to y, we get
⇒ 
On putting the values of y in equation 1, we get
⇒ 
⇒ 
⇒ 
⇒ 
Dimensions of the rectangular area:
x = 300
y = 60
Using safe research practices would be a very good common-sense practice in a lab environment.
Answer:
W and X
Explanation:
When escaping a rip current, one should always walk to the side until you escape from the rip current. If you walk towards the shore, you have the ability to keep getting dragged toward the current, such as with X and Y.
