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kramer
3 years ago
11

What happens when two charged objects physically contact each other?

Physics
1 answer:
kupik [55]3 years ago
6 0

If a negative object is used to charge a neutral object, then both objects become charged negatively if this answer is wrong I'm sorry.

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If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa
vladimir2022 [97]

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

◆ E = 100N

This is a Right answer...

I hope you understand...

7 0
3 years ago
Explain relative velocity briefly​
fomenos

Answer:

Explanation:

Relative velocity is defined as the velocity of an object B in the rest frame of another object A.

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At a constant pressure, melting occurs by A) producing energy. B) absorbing energy. C) releasing energy. D) circulating energy.
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A motionless mass, hung on the end of a spring and pulled 5 cm downward, is a height of 1 meter above the classroom floor
Travka [436]

Answer:

A

Explanation:

I TOOK IT

3 0
3 years ago
A 1. 30 kg block slides with a speed of 0. 855 m/s on a frictionless horizontal surface until it encounters a spring with a forc
boyakko [2]

a) For 0 compressions:

potential energy = U =  0 J

kinetic energy = k = 0.383 J

total mechanical energy = E = 0.383 J

b) For compression of 1 cm:

potential energy = U = 0.0228 J

kinetic energy = k = 0.155 J

total mechanical energy = E = 0.383 J

c) For compression of 2 cm :

potential energy = U = 0.1104 J

kinetic energy = k = 0.272 J

total mechanical energy = E = 0.383 J

d) For compression of 3cm:

potential energy  = U = 0.248 J

kinetic energy = k = 0.177 J

total mechanical energy = E = 0.383 J

<h3>Method for solving:</h3>

The equations for kinetic energy is:

k= 1/2*m*v^{2}

The equation for elastic potential energy is:

U= 1/2*ks*x^{2}

Where,

m= mass of the block

v= velocity

ks= spring constant

x= displacement of the spring

(a)when compression= 0 cm

U= 1/2*ks*v{2}

U= 1/2*552*(0)^{2}

 = 0 J

Kinetic energy:

k= 1/2*m*x^{2}

k= 1/2*(1.05)*(0.855)^{2}

k= 0.383 J

Mechanical energy:

E= k + U

E= 0.383+0

E= 0.383 J

There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance). This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).

(b) spring potential = ?

U= 1/2* 457 N/m*(0.01)^{2}

U= 0.0228 J

Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:

E= k + U

0.383= k + 0.0228

k= 0.383 - 0.228

k= 0.155

(c)spring constant when x= 0.02

U= 1/2*552*(0.02)^{2}

U= 0.1104 J

Using the equation of mechanical energy:

E= k +U

0.383= k+ 0.1104

k= 0.383 - 0.1104

k= 0.272 J

(d) U= 1/2*552*(0.03)^{2}

U= 0.2484 J

E= 0.383 J

k = E - U

k= 0.383- 0.206

k= 0.177

To learn more about spring potential energy visit:

brainly.com/question/28168175

#SPJ4

3 0
2 years ago
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