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qwelly [4]
3 years ago
7

By what mechanism is a person injured when he or she falls from a significant height? Select one: a. Kinetic energy is converted

to potential energy; the potential energy is then converted into the work of bringing the body to a stop. b. As the person falls, the amount of kinetic energy is converted into work; work is then converted to kinetic energy upon impact. c. Potential energy is created as the person is falling; the potential energy is then converted into kinetic energy upon impact. d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.
Physics
1 answer:
pashok25 [27]3 years ago
6 0

Answer:

d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop

Explanation:

- When the person starts his/her fall from a certain height h, he/she possesses gravitational potential energy:

U=mgh

where m is the mass of the person, g is the acceleration due to gravity, h is the height.

- During the fall, the height h decreases, while the speed of the person increases, so gravitational potential energy is converted into kinetic energy:

K=\frac{1}{2}mv^2

where

m is the mass of the person

v is the speed

- Just a moment before hitting the ground, h=0, so all the potential energy has been converted into kinetic energy

- When the person hits the ground, he/she comes a stop: this means that now the speed is zero (v=0), so the kinetic energy is zero as well. This occurs because all the kinetic energy has been converted into the work of bringing the body to a stop. (the work has been done by the ground on the person)

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Fluids can flow and change shape to fit their containers. Which two states are<br> fluids?
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<u>#{1} liquid</u>

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You are writing a report about space travel. Where would be the best place to find information? (2 points)
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Read 2 more answers
Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
Ket [755]

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

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θ = 65°

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a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

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Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

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Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

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