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kakasveta [241]
3 years ago
10

Find the missing lengths of the sides.

Mathematics
1 answer:
Anarel [89]3 years ago
6 0

Given:

The figure of a right angle triangle.

a=b

Hypotenuse = 9\sqrt{2} in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is 9\sqrt{2} in.

Using Pythagoras theorem, we get

Hyponteuse^2=Base^2+Perpendicular^2

(9\sqrt{2})^2=(a)^2+(b)^2

81(2)=(a)^2+(a)^2                    [\because a=b]

81(2)=2(a)^2

Divide both sides by 2.

81=(a)^2

Taking square root on both sides.

\pm \sqrt{81}=a

\pm 9=a

Side cannot be negative. So,

9=a

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

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Part A: The graph of the system is plotted at y-intercepts of 3 and -4. The line of the first equation is dashed and shaded below. The line of the second equation is dashed and shaded above. The solution area is between the second and third quadrants.

Part B: No, the point (-4, 6) is not in the solution are because it only fits into the first equations solution area. [6=2(-4)+3 solved is 6=-5, this is not a true statement.]

Step-by-step explanation:

Part A: Each equation {y>2x+3, y<-3/2x-4} is already in slope intercept form and can be graphed. In the first equation we know that there is a y-intercept of 3 and a slope of 2. This is shown as as a upward moving line with plot points such as (-2,-1), (-1,1), (0,4), (1,6), and so on. In the second equation we know that there is a y-intercept of -4 and a slope of -3/2. This is shown as a downward moving line with plot points such as (0,-4), (-2,-1), (-4, 2), and so on. (See graph below)

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So, already we know that this plot point is not an answer to the system. Let's continue anyway.

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