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kakasveta [241]
3 years ago
10

Find the missing lengths of the sides.

Mathematics
1 answer:
Anarel [89]3 years ago
6 0

Given:

The figure of a right angle triangle.

a=b

Hypotenuse = 9\sqrt{2} in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is 9\sqrt{2} in.

Using Pythagoras theorem, we get

Hyponteuse^2=Base^2+Perpendicular^2

(9\sqrt{2})^2=(a)^2+(b)^2

81(2)=(a)^2+(a)^2                    [\because a=b]

81(2)=2(a)^2

Divide both sides by 2.

81=(a)^2

Taking square root on both sides.

\pm \sqrt{81}=a

\pm 9=a

Side cannot be negative. So,

9=a

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

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Part A: Create a third-degree polynomial in standard form. How do you know it is in standard form? (5 points)
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Answer:

(See explanation for further details)

Step-by-step explanation:

a) Let consider the polynomial p(x) = 5\cdot x^{3} +2\cdot x^{2} - 6 \cdot x +17. The polynomial is in standards when has the form p(x) = \Sigma \limit_{i=0}^{n} \,a_{i}\cdot x^{i}, where n is the order of the polynomial. The example has the following information:

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b) The closure property means that polynomials must be closed with respect to addition and multiplication, which is demonstrated hereafter:

Closure with respect to addition:

Let consider polynomials p_{1} and p_{2} such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i} and p_{2} = \Sigma \limits_{i=0}^{n}\,b_{i}\cdot x^{i}, where m \geq n

p_{1}+p_{2} = \Sigma \limits_{i=0}^{n}\,(a_{i}+b_{i})\cdot x^{i} + \Sigma_{i=n+1}^{m}\,a_{i} \cdot x^{i}

Hence, polynomials are closed with respect to addition.

Closure with respect to multiplication:

Let be p_{1} a polynomial such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}

And \alpha an scalar. If the polynomial is multiplied by the scalar number, then:

\alpha \cdot p_{1} = \alpha \cdot \Sigma \limits_{i = 0}^{m}\,a_{i}\cdot x^{i}

Lastly, the following expression is constructed by distributive property:

\alpha \cdot p_{1} = \Sigma \limits_{i=0}^{m}\,(\alpha\cdot a_{i})\cdot x^{i}

Hence, polynomials are closed with respect to multiplication.

4 0
3 years ago
∠A and ∠B are supplementary, and ∠A and ∠C are supplementary. Which conclusion is valid? Select one: A. ∠B and ∠C are supplement
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Option D is the correct answer.

Answer:

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Step-by-step explanation:

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Since, ∠A and ∠C are supplementary.

Therefore,

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From equations (1) & (2)

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Answer:

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Step-by-step explanation:

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