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grigory [225]
3 years ago
6

6 students volunteer for a committee. How many different 3-person committees can be chosen?

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0
C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20
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What is the median of 76, 84, 93, 67, 82, 87, and 76?
Ahat [919]
The median of a set of numbers is the midpoint of the set if you were to organize the numbers from least to greatest or greatest to least. So, all we have to do is rearrange the numbers from least to greatest and find the midpoint:
67   76   76   82   84   87   93
count 3 in from both sides and the remaining number is 82, which is the median.
8 0
3 years ago
How many different 6-digit numbers can be formed by arranging the digits in 332345?
Feliz [49]

Answer- 120

Solution-

There are digits to be arranged,they are {3,3,2,3,4,5}. And from those ,3 digits are repeated .

so the total number of distinct number that can be formed = \frac{6!}{3!} = \frac{720}{6} = <em>120</em><em> </em>(ans)


7 0
4 years ago
What is the equation of this graphed line?
lorasvet [3.4K]
Slope: (y2-y1)/(x2-x1)
Points: (-4,-6), (2,6)
(6+6)/(2+6) = 12/8 = 3/2
Y = 3/2x +b
-6 = 3/2(-4) + b
-6 = -6 + b, b = 0
Equation: y = 3/2x
4 0
3 years ago
Make r the subject of the formula <br><img src="https://tex.z-dn.net/?f=v%20%3D%20%5Cpi%20%5C%3A%20h%20%7B%7D%5E%7B2%7D%28r%20-%
Vaselesa [24]

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

8 0
3 years ago
Consider Michelle and Gladys, two neighbors who each earn the same salary. Gladys pays less in federal income taxes than Michell
goldenfox [79]

Sad to say it is likely D.  If you are in the United States, I wouldn't know what deductions are available, but here are some possibilities.

1. Gladys is a single Mom. She gets to deduct her child.

2. Gladys owns her own home and gets to deduct her municipal tax. Michelle is renting and may be able to deduct something but not as much.

3. Gladys gets to deduct medical expenses. Michelle does not.

4. Gladys has a travelling allowance that is deductible. Michelle does not.

5. Gladys goes to church and tithes. Michelle does not.

6. Gladys has a registered savings plan. Michelle does not.

The problem is that the two women might very well be in a different tax bracket when all the deductions are considered. That depends on how the US system works. I don't think you are supposed to choose A. All other things being equal, they should be in the same tax bracket.

I don't see how B would come about. Usually state is dependent on Federal (it is in Canada anyway).

C is definitely wrong unless the savings plan is registered. Any savings plan that produces dividends or interest that is not registered is taxable.


8 0
3 years ago
Read 2 more answers
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