Hello :
if : a <span>≡ 5 ( mod 7) ....(1)
b </span><span>≡ 6 ( mod 7) ...(2)
(1)×(2) : ab </span><span>≡ 30 ( mod 7)
</span>but : 30 = 7×4 + 2 ..... so : 30 ≡ 2 ( mod 7)
then : ab ≡ 2 ( mod 7)
To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
Answer:
X=6 I believe
Step-by-step explanation:
Answer:
242
Step-by-step explanation:
1452÷ 6 would = 242
I hope this helped you!
Answer:
it b
Step-by-step explanation:
