Question

How do you solve this?

Answer 1

Use BEDMAS:

B - Brackets

E - Exponents

D - Division

M - Multiplication

A - Addition

S - Subtraction

$6-\dfrac{18-3^2}{4+(2-3)}=6-\dfrac{18-9}{4+(-1)}=6-\dfrac{9}{3}=6-3=3$

Answer 2

Here is the equation:

$6-\frac{18-3^{2}}{4+(2-3)}$

Use PEMDAS

$Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction$

Parentheses is first:

$2-3 = -1$

Next is exponents:

$3^{2} = 3 \times 3 = 9$

Your new equation is:

$6-\frac{18-9}{4+(-1)}$

Simplify the fraction:

$\frac{18-9}{4+(-1)} = \frac{9}{3} = 3$

Your new equation is:

$6-3$

Subtract:

$6-3=3$

Your answer is:

$6-\frac{18-3^{2}}{4+(2-3)} = \bf 3$