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Oxana [17]
3 years ago
8

Ronnie operates a lawn care service. on each day, the cost ofmowing the first lawn is $10: the cost of mowing the second lawn is

$12: and the cost of mowing the third lawn is $15. His producersurplus on the first three lawns of the day is $53. if Ronniecharges all customers the same price for lawn mowing, that priceis.
a. $25
b. $30
c. $36
d. $45
Business
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

b. $30

Explanation:

producer surplus = price producer able to sell - price producer would be willing to sell

⇔ price producer able to sell = producer surplus + price producer would be willing to sell = 53 + (10+12+15) = $90 for 3 lawn

if Ronnie charges all customers the same price for lawn mowing, that price is $30 (= $90/3)

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Bulluck Corporation makes a product with the following standard costs: Standard Quantity or Hours Standard Price or Rate Direct
avanturin [10]

Answer:

Variable overhead efficiency variance= $544 favorable

Explanation:

Giving the following information:

Variable overhead 0.90 hours $ 3.40 per hour

Actual output 4,400 units

Actual direct labor-hours 3,800 hours

<u>To calculate the variable overhead efficiency variance, we need to use the following formula:</u>

<u></u>

Variable overhead efficiency variance= (Standard Quantity - Actual Quantity)*Standard rate

Variable overhead efficiency variance= (3,960 - 3,800)*3.4

Variable overhead efficiency variance= $544 favorable

Standard quantity= 4,400*0.9= 3,960

8 0
3 years ago
. A one-product firm estimates that its daily total cost function (in suitable units) is C (x) = x^3 - 6x^2 + 13x + 15 and its t
givi [52]

Answer:

Value of x maximising profit : x = 5

Explanation:

Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x

Profit : Revenue - Cost = R(x) - C(x)

28x - [x^3 - 6x^2 + 13x + 15]  = 28x - x^3 + 6x^2 - 13x - 15

= - x^3 +  6x^2 + 15x - 15

To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.

dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0

3x^2 + 3x - 15x - 15 = 0  ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0

x + 1 = 0 ∴ x = -1   [Rejected, production quantity cant be negative] ;

3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5

Double derivate : d^2TP/dx^2 = - 6x + 12

d^2TP/dx^2  i.e - 6x + 12  at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5

8 0
4 years ago
Frank and lillian gilbreth developed the principle of _________, which said that every job could be broken down into a series of
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3 0
3 years ago
2. Shoplifting is a very serious problem for retail store owners, with millions of dollars of merchandise stolen each year. Obvi
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Assume a company has a cost of capital that is greater than zero and has cash flows related to the changes in net working capita
Otrada [13]

Answer:

A. Decrease

Explanation:

In investment appraisal with the method of Net Present Value, the bone of contention and the central matter is the TIME VALUE OF MONEY.

In the above scenario, the initial working capital was 100% released in proportions of 40%, 40% and 20%, throughout the 3 years of the project. However, if the reverse had been the case, i.e. parting with more cash now and the requirement of working capital now becomes: Year 0 = -10,000, Year 1 = - 10,000, Year 2 = -10,000, Year 3 = +30,000; the NPV would definitely shrink because the value of 10,000 each in Years 0-2 would not be the same when it is recovered from the project in year 3. The value will be smaller and hence the NPV of the project would have decreased as a result of the time value of money.

7 0
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