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andrey2020 [161]
3 years ago
8

What should I do ???

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0
Hello!

Areas of quadrilaterals follow the formula A = bh, where b is the base and h is the height. What this formula means is you multiply the base length by the height length and you will have the area. The important thing to remember when calculating area is that the result will always be in units squared (example: 24 cm²). I'll do a few:

1) A = bh
    A = 8(2)
    A = 16 units²

(Since there is no unit given, just use the word units.)

2) A = 8(9)
    A = 72
    A = 72 units²

3) A = 6(5)
    A = 30
    A = 30 units²

I hope this helps you!
a_sh-v [17]3 years ago
3 0
To find the area, you would multiply length times width.
For example, to find the area of problem number 1, I would multiply 8 (length) times 2 (width) to get the area of 16.
I hope this helped! If you need another example, feel free to ask!
:-)
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3 years ago
!!20 POINTS!! Claire filled up her car with gas before embarking on a road trip across the country. Let G represent the number o
pentagon [3]

Answer:

G=-\frac{5}{4}t+15

Slope = -\frac{5}{4}

Step-by-step explanation:

Let the equation representing the number of gallons left in the gas tank is,

G = mt + b

Where m = slope of the line

b = y-intercept of the line

Slope of the line passing through two points (x_1,y_1) and (x_2,y_2) is,

'm' = \frac{y_2-y_1}{x_2-x_1}

Slope of the line passing through (8, 5) and (4, 10),

m = \frac{10-5}{4-8}

m = -\frac{5}{4}

Equation of line will be,

G = -\frac{5}{4}t+b

Since, point (8, 5) lies on this line,

5 = -\frac{5}{4}(8)+b

5 = -10 + b

b = 15

Therefore equation of the function will be,

G = -\frac{5}{4}t+15

Here slope of the function represents the \frac{5}{4} gallons of gas is consumed to drive the car for one hour.

4 0
2 years ago
The first quartile in a box-and-whisker plot would be located on what number?
astraxan [27]

Answer:

24.5

Step-by-step explanation:

When you round it you get 25. (sorry if im wrong) :(

4 0
2 years ago
Wasn’t sure how to write this out : - )
amid [387]

we are given

\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}

we can write it in terms of exponents

\frac{7^{\frac{1}{3}}*7^{\frac{1}{2}}}{7^{\frac{5}{6}}}

Firstly , we will simplify numerator

\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}

now, we can add exponents

\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}

we can cancel it

and we get

=1............Answer

5 0
3 years ago
PLEASE HELP! THANK YOU!!!
Ronch [10]

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3(x - 2) = 12

x = 6

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6(x + 5) = 54

x = 4

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3x  +  5 = 32

x = 9

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5(x + 7) = 45

x = 2

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7x + 6 = 41

x = 5

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2(x + 7) = 29

x = 7.5

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4(x + 3) = 30

x = 4.5

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5(x - 4) = 20

x = 8

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3x - 10 = 23

x = 11

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

7 0
2 years ago
Read 2 more answers
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