The values of cosine Ф and cotangent Ф are
and -1
Step-by-step explanation:
When a terminal side of an angle intersect the unit circle at
point (x , y), then:
- The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
- The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
- If x and y coordinates are positive, then the angle lies in the 1st quadrant
- If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
- If x and y coordinates are negative, then the angle lies in the 3rd quadrant
- If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant
∵ The terminal ray of angle Ф intersects the unit circle at point 
- According to the 1st and 2nd notes above
∴ cosФ = x-coordinate of the point
∴ sinФ = y-coordinate of the point
∵ The x-coordinate of the point is negative
∵ They-coordinate of the point is positive
- According the the 4th note above
∴ Angle Ф lies in the 2nd quadrant
∵ x-coordinate = 
∴ cosФ = 
∵ y-coordinate = 
∴ sinФ = 
- cotФ is the reciprocal of tanФ
∵ tanФ = sinФ ÷ cosФ
∴ cotФ = cosФ ÷ sinФ
∴ cotФ =
÷ 
∴ cotФ = -1
The values of cosine Ф and cotangent Ф are
and -1
Learn more:
You can learn more about the trigonometry function in brainly.com/question/4924817
#LearnwithBrainly
The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³
and that's exactly the same as
( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres
is the cube of the ratio of their radii.
Earth radius = 6,371 km
Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note:
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.
<span>C; words per minute, because the independent quantity is the minutes.
hope this helps!
</span>
Answer:
15cm
Step-by-step explanation:
All you need to do for this is divide the perimeter (60) by the number of sides on a square (4). 60÷4=15