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2 years ago

Can someone plspls help me with the middle one tysm if you do i rlly need the help!!!:)).

Mathematics

1 answer:

adell [148]2 years ago

6 0

Answer:

360

Step-by-step explanation:

60%= 60/100

540/x=60/100

x=900

900-540=360

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Expand and simplify 2/5(p+15)-1/3(9+6p)+4/5p

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3 years ago

At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round

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Answer:

$Meeting\ Time = 6:03\ pm$

Step-by-step explanation:

Given

$Start\ Time= 5:45pm$

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

$Devi = 4minutes/2\ rounds$

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

Convert 360 seconds to minutes

$Khairul = \frac{360}{60} min/round$

$Khairul = 6 min/round$

$Devi = 4minutes/2\ rounds$

Divide by 2/2

$Devi = 2mins/round$

So, we have:

$Lixin = 18\ min/round$

$Khairul = 6 min/round$

$Devi = 2mins/round$

Next, is to determine the LCM of 18, 6 and 2

$18=2 * 3 * 3$

$6 = 2 * 3$

$3 = 3$

Their LCM is:

$LCM = 2 * 3 * 3$

$LCM = 18$

This means that they will meet 18 minutes after their initial time of departure.

So:

$Meeting\ Time = 5:45\ pm + 18\ minutes$

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2 years ago

What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S

Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

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2 years ago

For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exerc

pav-90 [236]

Answer:

Step-by-step explanation:

The record of the statistics and the summary statistics which are the missing files in the question are attached below.

From the given information:

The null hypothesis and the alternative hypothesis can be represented by :

$\mathbf{H_o:}$ There is no difference between the average time spend by men and women at gym each week

$\mathbf{H_i:}$ The average time spend by men is greater than the average time spend by women at the gym each week

From the summary statistics in the attached file below:

The p-value = 0.3253

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Therefore; it is obvious that the p-value is greater than the level of significance i.e (0.3253 > 0.05)

Hence; there is no enough evidence to reject the null hypothesis

CONCLUSION: We conclude that the mean number of minutes exercised per week is larger for men than women at the this gym.

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3 years ago