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3 years ago

HELP PLEASE ASAP! What is the domain of the relation?

Mathematics

1 answer:

Kitty [74]3 years ago

3 0

The answer is D(-4,-2,2) The domain of a relation is always the x values and the range is always the y values.

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How do you work out 9/10 divided by 6/7??

Helga [31]

$\frac{9}{10} \div \frac{6}{7}$
You just flip 6/7 so it would be 7/6 and then you times it.
$\frac{9}{10} \div \frac{6}{7}$
$\frac{9}{10} \times \frac{7}{6} = \frac{63}{60} = \frac{21}{20}$

6 0

3 years ago

Help me with this Please.

sukhopar [10]

35
the ratio for the two is 5:7 and you want to find _:49. to get from 7 to 49 you multiply the 7 by 7. because you did that to one side you have to do the same to the other and multiply 5 by 7 which gives you 35

6 0

2 years ago

Someone please help me

Ratling [72]

Answer:

1 mi/1.61 km

Step-by-step explanation:

we know that

1 mile= 1.61 kilometers

To convert 1 kilometer to miles

use proportion

1/1.61 mi/km=x/1 mi/km

x=1 mi/1.61 km

5 0

3 years ago

Read 2 more answers

Find a point-slope form for the line with slope 1 over 5 and passing through the point -8, -7

Whitepunk [10]

Answer:

(1/5)x-5.4=y

Step-by-step explanation:

mx+b=y

m=(1/5)

(-8,-7)=(x,y)

(1/5)(-8)+b=(-7)

-1.6+b=-7

b=-5.4

(1/5)x-5.4=y

6 0

3 years ago

Calculate the average rate of change for the function f(x) = x4 + 3x3 - 5x2 + 2x - 2, from x = -1 to x = 1

kolezko [41]

In interval <a, b> the average rate of change the function you count from this formula:
$x=\frac{f(b)-f(a)}{b-a} \qquad b>a$
Here you've got a=-1 and b=1:
$f(a)=f(-1)=(-1)^4+3 \cdot (-1)^3 - 5 \cdot (-1)^2 +2 \cdot (-1)-2= \\ = 1-3-5-2-2=-11 \\ \\ f(b)=f(1)=1^4+3 \cdot 1^4 - 5 \cdot 1^2 + 2 \cdot 1 -2=1+3-5+2-2=-1 \\ \\ \hbox{So average rate of change this function is:} \\ \\ x= \frac{-1+11}{1+1}=\frac{10}{2}=5$

5 0

3 years ago

Read 2 more answers