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ira [324]
4 years ago
12

What is the wavelength of an X-ray photon with energy 8.0 keV (8000 eV)? (1 eV = 1.60 × 10−19 joule.)

Physics
1 answer:
katrin2010 [14]4 years ago
3 0

Answer:

Wavelength = 0.15 nm

Frequency = 1939.3939\times 10^{15}Hz

Explanation:

We have given photon energy E = 8 KeV = 8000 eV

In question it is given that 1eV=1.6\times 10^{-19}J

So 8000eV=1.6\times 8000\times 10^{-19}=12800\times 10^{-19}j

Plank's constant h=6.6\times 10^{-34}js

We know that photon energy is given by E=h\nu

So 12800\times 10^{-19}=6.6\times 10^{-34}\nu

\nu =1939.3939\times 10^{15}Hz

Now wavelength \lambda =\frac{c}{f}=\frac{3\times 10^8}{1939.3939\times 10^{15}}=0.0015\times 10^{-7}m=0.15nm

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Explanation:

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Credit : This is used to show the decrease in asset or increase in liability or owners equity account.

Matching principle : This principle states that expenses and revenue should be assigned to their correct accounting period. It states that all expenses earned during the financial period either paid for or unpaid and all income earned either received or not received must be recorded and treated in that financial period.

Expenses: This is the amount of money spent in the performance of business activities, example of these is the cost of goods and services used up in the process of generating revenue for the business.

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When an electron jumps to or from one energy level to another energy level, spectral lines are produced. The range of spectral lines depends on the number of energy levels available to which the electron can jump. This depends the amount of energy gained/lost by the electron.

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