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Crank
3 years ago
13

Which atomic model was proposed as a result of j. J. Thomson’s work?

Physics
1 answer:
EleoNora [17]3 years ago
4 0
<h2>Answer: The "raising pudding" atomic model</h2>

Explanation:

<u>During the 19th century the accepted atomic model, was Dalton's atomic model</u>, which postulated the atom was an <u>"individible and indestructible mass".</u>

However, at the end of 19th century J.J. Thomson began experimenting with cathode ray tubes and found out that atoms contain small subatomic particles with a negative charge (later called <u>electrons</u>).  This meant the atom was not indivisible as Dalton proposed. So, Thomson developed a new atomic model.

Taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons (with negative charge) were immersed in the atom of positive charge that counteracted the negative charge of the electrons. <u>Just like the raisins embedded in a pudding or bread. </u>

That is why this model was called the <u>raisin pudding atomic model.</u>

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When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rat
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0.2289

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3 years ago
Two concrete spans of a 380 m long bridge are
Mazyrski [523]

Answer:

4.163 m

Explanation:

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L = 380 m

And the bridge consists of 2 spans, the initial length of each span is

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Due to the increase in temperature, the length of each span increases according to:

L_f = L_i(1+ \alpha \Delta T)

where

L_i = 190 m is the initial length of one span

\alpha =1.2\cdot 10^{-5} ^{\circ}C^{-1} is the temperature coefficient of thermal expansion

\Delta T=20^{\circ}C is the increase in temperature

Substituting,

L_f=(190)(1+(1.2\cdot 10^{-5})(20))=190.0456 m

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h=\sqrt{L_f^2-L_i^2}=\sqrt{(190.0456)^2-(190)^2}=4.163 m

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3 years ago
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