We use the kinematics equation:
Vf = Vi + a*t
8 = 0 + 3.6 * t
t=2.222s to reach 8.0 m/s
At that time the train has moved
4.5 m/s * 2.222s = 9.999 m
He travelled (another kinematics equation)
Vf^2 = Vi^2 + (2*a*d)
(8.0)^2 = (0)^2 + (2 * 3.6 * d)
d=8.888 m
The train is 9.999m, the fugitive is 8.888m,
He still needs to travel
9.999-8.888= 1.111m
He needs to cover the rest of the distance in a smaller amount of time, however hes at his maximum velocity, so...
8m/s(man) - 4.5m/s(train) = 3.5 m/s more
(1.111m) / (3.5m/s) = .317seconds more to reach the train
So if it takes 2.222 seconds to approach the train at 8.888m, it should take
2.222 + .317 =2.529 seconds to reach the train completely
Last but not least is to figure out the total distance traveled in that time frame:
(Trains velocity) * (total time)
(4.5m/s)*(2.529s)=11.3805m
Answer:
30,000 kgms⁻¹
Explanation:
Momentum = mass x velocity, 1000 x 30. Hence, your answer.
This Question has mistakes.Correct question is
An undamped oscillator has period τo=1.000s
, but I now add a little damping so that its period changes to τ1=1.001s.
What is the damping factor β? By what factor will the amplitude of oscillation decrease after 10 cycles? Which effect of damping would be more noticeable, the change of period or the decrease of the amplitude?
Answer:
β=0.28 /sec
Amplitude=0.0606
Explanation:
Answer:
Friction force is equal to the coefficient of friction times the normal force.
Explanation:
It does not really matter if the force is side or not. You need to draw a free body diagram, add weight, normal force, friction force and active force. Then see the horizontal and vertical components to calculate what is the normal force.
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