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lyudmila [28]
2 years ago
11

As a skateboarder moves up a ramp how does her potential energy change

Mathematics
1 answer:
uysha [10]2 years ago
7 0
B as the skateboarder moves up hee potential energt increases
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Hi doe s anyone know the answer
Svetlanka [38]

Answer:

<u>Regular Polygon:</u>

<em>C, E  </em>(All sides and angles are equal)

<u>Irregular Polygon:</u>

<em>A, B, </em>(Not all sides or angles are equal)

<u>Not a Polygon</u>

<em>E, F </em>(There are curves and not a closed shape)

Hope this helps! Comment if you have any questions :)

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5 0
3 years ago
Read 2 more answers
Solve for the indicated variable 4c=d for c
Georgia [21]
<em>∙•❁</em>Okay so we are going to solve for c so lets begin.<em>❁•∙ </em>

4c=d

<em>∙•❁</em>We are going to divide both sides by 4.

\frac{4c}{4}= \frac{d}{4}

<em>∙•❁</em>Your Final answer is:

c= \frac{1}{4}d

<em>∙•❁I hope this helps!❁•∙ </em>
8 0
3 years ago
Why is it important to include the units in a rate
bija089 [108]

Answer:

Unit rates are useful because they allow you to make direct comparisons. For example, you have your choice between two bottles of ketchup.

Step-by-step explanation:

7 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
Pedro fez a seguinte crítica: "O gráfico traz números absolutos, indicando que São Paulo tem muito mais mortes no trânsito que N
pochemuha

Answer:

i dont speak spanish

Step-by-step explanation:

7 0
3 years ago
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