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valentinak56 [21]

3 years ago

11

Georgia Bulldogs football team played 10 games in the 2020-21 season those games they won eight and lost 2 what percentage of th

eir games did they win?
80%

20%

25%

8%

1 answer:

gavmur [86]3 years ago

5 0

Answer:

80% i think

Step-by-step explanation:

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If M9=119,what is the sum of the measures 0f 11 and 16?

mote1985 [20]

The answer is: " 132° " .
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Note: m∠9 = m∠11 = m ∠16 ;

So; m∠11 + m∠16 = 132 .
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7 0

3 years ago

The distance from Boston to Philadelphia by plane is 436 kilometers. A pilot flies this route 252 times. Does the pilot travel m

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4 years ago

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If x + 9 = 5 then x =<br> If x + 9 = -5 then x =

guajiro [1.7K]

Answer:

If x + 9 = 5 then x =- 4

If x + 9 = -5 then x =-14

Step-by-step explanation:

x+9 =5

Subtract 9 from each side

x+9-9 = 5-9

x = -4

x+9 = -5

Subtract 9 from each side

x+9-9=-5-9

x = -14

4 0

3 years ago

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What expression shows the distance on the number line between −12 and −1 ?<br><br> Thxxs! ^^

docker41 [41]

-12 and -1 are 11 units apart.
-12-(-1) = -11
The absolute value which is just the number of units is 11.
Hope this helps you

4 0

3 years ago

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

3 years ago