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valentinak56 [21]
3 years ago
11

Georgia Bulldogs football team played 10 games in the 2020-21 season those games they won eight and lost 2 what percentage of th

eir games did they win?
80%

20%

25%

8%
Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

80% i think

Step-by-step explanation:

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Which rational number is equivalent to the expression 69 2/9 - 31 1/9 - (-12 4/9) ?
ololo11 [35]

Answer:69 2/9 - 31 1/9 - (- 12 4/9) =

69 2/9 - 31 1/9 + 12 4/9 =

81 6/9 - 31 1/9 =

50 5/9 or 455/9 or 50.56 <==

Step-by-step explanation:

7 0
3 years ago
Help wanted pls math
Serjik [45]

Answer:

39 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

Let:

base = b = 4 ft

height = h = 3 ft

Solve for the area of the triangle:

A = 1/2(4)(3)

A = 2 * 3

A = 6 ft²

Area of a rectangle = bh

Let:

base = b = 9 ft

height = h = 5 ft

Solve for the area of the rectangle:

A = (9)(5)

A = 9 * 5

A = 45 ft²

Subtract the area of the triangle from the area of the rectangle:

45 - 6 = 39 ft²

39 ft² is your answer.

~

3 0
3 years ago
Read 2 more answers
Write down the 1st term in the sequence given by: T(n) = n2 + 3
polet [3.4K]
If its first term, n is equal to 1. Thus...

T(1)=(1)(2)+3=2+3=5

The answer is 5.
7 0
3 years ago
Find the measure of angle 1.
Mamont248 [21]

Angle 1 would be 8x-4 because it is opposite to the other 8x-4 angle.

5 0
3 years ago
Use the unit circle to evaluate these expressions:
sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

So then sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

And we know that \frac{7\pi}{6} is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}

c) For this case that any factor of \pi the sin function is equal to 0.

So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

So then sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

And we know that \frac{7\pi}{6} is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}

c. tan(450pi)

For this case that any factor of \pi the sin function is equal to 0.

So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

4 0
3 years ago
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