Algebraically solve the inequality: 5x-6>/1+2(4x+1)
1 answer:
You might be interested in
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), 
and 
are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
Now that we have our quadratic function, we are going to use the average formula:
is the function evaluated at the <span>9th month
</span>
is the function evaluated at the 3rd month
![m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7B%5B9%5E%7B2%7D-24%289%29%2B108%5D-%5B3%5E%7B2%7D-24%283%29%2B108%5D%7D%7B9-3%7D%20)
We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>
Now that we have our quadratic function, we are going to use the average formula:
</span>
We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>
Answer:
Option C
Step-by-step explanation:
Note that the relation describing the set of ordered pairs does not change at a costing rate
Therefore the relationship is not linear.
However, the exchange rate increases by a factor of 2 units when n increases 1 unit. This allows us to conclude that the relationship is quadratic
Note that the following ordered pairs belong to the function
A = {(2, 4), (3, 9), (4, 16), (5, 25)}
The set of ordered pairs that we have is:
B = {(2, 2), (3, 7), (4, 16), (5, 23)}
Note that there is a similarity between both sets of ordered pairs.
In set B the values of y are always 2 units less than the values in y of the set A.
Then we deduce that since the function that models the set A is then the function that contains the ordered pairs of the B set is:
The correct option is option C)