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3 years ago

An explosion occurs 34 km away. The time it takes for its sound to reach your ears, traveling at 343 m/s, is

Physics

2 answers:

madam [21]3 years ago

7 0

Answer: 99.1 seconds

Explanation: You know that the total distance is 34km, and the speed of the sound is 343m/s.

Now, the total time that takes to something with a given velocity, to reach a distance D, is:

T = D/v

where D = 34km and v = 343m/s

Now, here we have different units, so we must convert the kilomeres into meters, this can be done as: 1km = 1000m then, 34km = 1000*34m = 34000m

Then the total time is:

T = 34000m/343m/s = 99.1 seconds

Ostrovityanka [42]3 years ago

6 0

Answer:

99 s

Explanation:

distance = rate × time

34000 m = (343 m/s) t

t = 99 s

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Using the periodic table, choose the more reactive metal. Al or Mg

ziro4ka [17]

Aluminum, and magnesium are metals. For metals, reactivity decreases as you go from left to right across the periodic table. Atomic number of Al is 13 and of Mg is 12. Hence the least reactive of these two is therefore aluminum.

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Aluminum will not react to simple flame, it will only melt with enough direct heat.

Magnesium
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Atomic Number: 12
Atomic Symbol: Mg
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Electron Configuration: 2-8-2

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========
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3 years ago

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If an astronaut goes on a space walk outside the Space Station, she will quickly float away from the station unless she has a te

Strike441 [17]

Answer:

d. This statement is false. She and the Space Station share the same orbit and will stay together unless they are pushed apart.

Explanation:

In astronomy, orbit is simply a path of an object around another object in a space. That is, orbit is a path of a body that revolves around a gravitating center of mass. Examples of an orbit is are satellite around a planet, orbit around a center of galaxy, planet around the sun, and among others.

On the other hand, space station refers to a spacecraft that can support a group of human for long time in the orbit. Another names for space stations are orbital space station and orbital station.

Therefore, an astronaut goes on a space walk outside the Space Station shares the same orbit with the space station and they will stay together unless they are pushed apart.

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Scientists can use the location and depth of where a fossil is found to estimate the age of the fossil. To do this, they use

Roman55 [17]

Answer:

C the Law of Superposition

Explanation:

Basically the law of Superposition is applied in this regard. The law states that "the oldest layer is on the bottom and the youngest layer is on top".

When we find fossils at a particular depth we can relatively date a rock based on the strata we find them. A fossil in place in bottom beds will be older than the one in the topmost layer. Fossils also succeed one another in a definite pattern according to the principle of fossil and fauna succession.

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3 years ago

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A pot on the stove contains 200 g of water at 20°C. An unknown mass of ice that is originally at −10°C is placed in an identical

Mumz [18]

Answer:

a) The mass of the ice is smaller than the mass of the water

b) The ice reaches first 80°C ,

Explanation:

Since the heat Q that should be provided to ice

Q = sensible heat to equilibrium temperature (as ice) + latent heat + sensible heat until final temperature ( as water)

m ice * c ice * ( T equil -T initial ) + m ice* L + m ice* c water * ( T final - T equil)

and the heat Q that should be provided to water is

Q= m water * c water * ( T final - T equil )

since the rate of heat addition q = constant and the time t taken to reach the final temperature is the same , then the heat absorbed Q=q*t is the same for both, therefore

m water * c water * ( T final - T equil ) = m ice* [c ice *( T equil -T initial ) + L + c water * ( T final - T equil)]

m water/ m ice = [c ice * ( T equil -T initial ) + L + c water * ( T final - T equil)]/ [ c water * ( T final - T equil)]

m water/ m ice = [c ice * ( T equil -T initial ) + L ]/[c water * ( T final - T equil) ] + 1

since [c ice * ( T equil -T initial ) + L ]/[c water * ( T final - T equil) ] >0 , then

m water/ m ice > 1

m water > m ice

so the mass of ice is smaller that the mass of water

b) Since the heat Q that should be provided to the ice, starting from 55°C mass would be

Q ice= m ice * c water * ( T final2 - T final1 )

and for the water mass

Q water = m water * c water * ( T final2 - T final1 )

dividing both equations

Q water / Q ice = m water / m ice >1

thus

Q water > Q ice

since the heat addition rate is constant

Q water = q* t water and Q ice=q* t ice

therefore

q* t water > q* t ice

t water > t ice

so the time that takes to reach 80°C is higher for water , thus the ice mass reaches it first.

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4 years ago