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2 years ago

5

-How can a camera help someone see something he or she wouldn't normally be able to see?

1 answer:

joja [24]2 years ago

4 0

Answer:

》How can a camera help someone see something he or she wouldn't normally be able to see?

- Although the human eye is able to observe fast events as they happen, it is not able to focus on a single point of time. We cannot freeze motion with our eyes. With a camera, however, so long as there is enough light, we can freeze motion. ... The camera can capture 'the moment', while your eye cannot.

》In what way is laser different from light produced by other sources?

-The major difference between laser light and light generated by white light sources (such as a light bulb) is that laser light is monochromatic, directional and coherent. ... Light from a conventional sources, such as a light bulb diverges, spreading in all directions.

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A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 3

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2. What is the gravitational force on a 70.0 kg object that is 3.18 x 10 ^6m on the

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A ball is thrown vertically upward with a velocity of 115m/s. Show work

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3 years ago

To pull a 57 kg crate across a horizontal frictionless floor, a worker applies a force of 230 N, directed 34° above the horizont

lisabon 2012 [21]

Answer:

$a. W_w=235\ J\\b. W_g=-343.54\ J\\c. F_N=463.100\ N\\d. W_t=235\ J$

Explanation:

Given: that,

Angle of inclination of the surface, $\theta=34^{\circ}$

mass of the crate, $m=57\ kg$

Force applied along the surface, $F=230\ N$

distance the crate moves after the application of force, $s=1.1\ m$

a) work done = F× s

work done = 230 × 1.1

work done = 253 J

b) Work done by the gravitational force:

$W_g=m.g\times h$

where:

g = acceleration due to gravity

h = the vertically downward displacement

Now, we find the height:

$h=s\times sin\ \thetah=1.1\times sin\ 34^{\circ}h=0.615\ m$

So, the work done by the gravity:

$W_g=57\times 9.8\times (-0.615) \\= - 343.54 J$

∵direction of force and displacement are opposite.

= - 343.54J

c)

The normal reaction force on the crate by the inclined surface:

$F_N=m.g.cos\ \thetaF_N=57\times 9.8\times cos\ 34F_N=463.100\ N$

d)

Total work done on crate is with respect to the worker:

$W_t=235\ J$

5 0

3 years ago