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Allushta [10]
3 years ago
13

Why can gases and liquids both transmit heat by convection?

Physics
2 answers:
defon3 years ago
6 0

Answer:

A. Their particles are free to move away from each other.

Explanation:

DochEvi [55]3 years ago
4 0

Answer:

Gases and liquids both transmit heat by convection because <u><em>their particles are free to move away from each other (option A).</em></u>

Explanation:

Convection is a process in which heat is transferred between two liquid substances, between two gaseous substances or a gas and a liquid when they are at different temperatures. The heat flux is produced from the body with the highest temperature to the substance with the lowest temperature.

The transmission of heat by convection is based on the actual movement of the molecules of a substance. Both liquids and gases are considered fluids where their particles are free to move away and move from each other. In solids particles vibrate around fixed positions and have a fixed volume .

<u><em>Gases and liquids both transmit heat by convection because their particles are free to move away from each other (option A).</em></u>

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3 years ago
A)If your torsion balance deflects to an angle of 10° when your two spheres are 40cm apart, what angle will it deflect to when t
svp [43]

Answer:

Explanation:

Given

for \theta=10^{\circ}

Sphere are d=40\ cm

when sphere d_2=10\ cm apart suppose deflection is \theta _2

We know

F=k_t\cdot \theta

Where F=force between charged particle

\theta =Deflection

F=\frac{kQ_1Q_2}{r^2}=k_t\cdot \theta

\theta =\frac{k}{k_t}\times \frac{Q_1Q_2}{r^2}----1

thus \theta \propto \frac{1}{r^2}

for \theta _2

\frac{\theta _1}{\theta _2}=(\frac{r_2}{r_1})^2

\theta _2=16\times \theta _1

\theta _2=160^{\circ}

(b)for 10^{\circ} deflection Potential v_1=8\ kV

Electric Potential is V=\frac{kQ}{r}

Q=\frac{V\cdot r}{k}

where V=voltage

k=constant

r=distance between charges

Put value of Q in equation 1

\theta =\frac{k}{k_t}\times \frac{V^2r^2}{k^2}

\theta =\frac{V^2r^2}{k\cdot k_t}

thus \theta \propto V^2

therefore

\frac{\theta _1}{\theta _2}=(\frac{V_1}{V_2})^2

\frac{10}{\theta _2}=(\frac{8}{4})^2

\theta _2=\frac{10}{4}=2.5^{\circ}

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3 years ago
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3 years ago
Read 2 more answers
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