Last question, can someone help please?
1 answer:
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Answer:
Natural frequency=21.40 Hz
Time= 0.2936 seconds
Explanation:
Idealizing the question as a cantilever beam with point load of mass M as 20 tons
Lateral stiffness, where l is length given as 10 m, E is Young’s modulus given as 30GPa and I is inertia where for a circular cross-section is given by
k== 9160884.178
k=
To find the frequency, , the mass m is given as 20 tons or 20000 Kg
=21.40196741 Hz
Natural frequency=21.40 Hz
Time period,
T==0.2935798 seconds
T=0.2936 seconds
Answer:
a) R(fw) = 46.75*10⁶ (N)
b) R(rwi) = 70.125*10⁶ [N]
Explanation: See Attached file (the rectangle stands for a jet)
The diagram shows forces acting on the jet
Let R(fw) Reaction of front wheels and
R(rw) Reaction of rear wheels
Now we apply the Stevin relation, for R(fw) and a jet weight as follows
R(fw)/ 4 = 187*10⁶ / 16
Then :
R(fw) = ( 1/4) *187*10⁶ ⇒ R(fw) = 46.75*10⁶ (N)
And e do the same for the reaction on rear wheels
R(rw) / 12 = 187*10⁶ /16 ⇒ R(rw) =(3/4)*187*10⁶
R(rw) = 140,25*10⁶ [N]
The last expression is for the whole reaction, and must be devide by 2
because that force is exerted for two wheels, therefore on each of the two rear wheels the reaction will be:
R(rwi) = 70.125*10⁶ [N]
Answer:
Explanation:
Force on a current carrying rod due to magnetic field is given as
here we know that
current in the rod
now magnetic force is balanced by the weight of the rod
so we will have