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podryga [215]
3 years ago
11

The dimensions for force are the product of mass and length divided by time squared. Newton's second law states that force equal

s the product of mass and acceleration. What are the dimensions of acceleration?
T2
T2/L
L/T2
L/T
Physics
1 answer:
maw [93]3 years ago
5 0

Answer:

L/T^2.

Explanation:

Dimensional analysis is defined as the analysis of the relationships between different physical quantities by identifying their base quantities (such as length, mass, time, temperature etc.) and units of measure (such as miles vs. kilometers, pounds vs. kilograms etc.).

F = m * a

kg(m/s^2) = kg * a

In dimensions,

a = L/T^2.

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3 0
3 years ago
If it requires 3.0 J of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re
-BARSIC- [3]

Answer:

Work done = 13605.44

Explanation:

Data provided in the question:

For elongation of 2.1 cm (0.021 m) work done by the spring is 3.0 J

The relation between Energy (U) and the elongation (s) is given as:

U = \frac{1}{2}kx^2   ................(1)

where,

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on substituting the valeus in the above equation, we get

3.0 = \frac{1}{2}k\times0.021^2

or

k = 13605.44 N/m

now

for the elongation x = 2.1 + 4.1 = 6.2 cm = 0.062 m

using the equation 1, we have

U = \frac{1}{2}\times13605.44\times (0.062)^2

or

U = 26.149 J

Also,

Work done = change in energy

or

W = 26.149 - 3.0 = 23.149 J

4 0
2 years ago
2. An electron and a proton are separated by 5 cm:
Diano4ka-milaya [45]

Answer:

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2 years ago
A QL = -26 μC charge is placed on the x-axis at x = - 0.2 m. A QR = 26 μC charge is placed at x = +0.2 m. (for all answers below
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<span>You are given a QL = -26 μC charge that is placed on the x-axis at x = - 0.2 m and a QR = 26 μC charge that is placed at x = +0.2 m. The answers are:

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</span>
4 0
3 years ago
How can I convert this?<br>Please answer with solution. Thank you.​
fomenos

Answer:

1 hr 45 min

Explanation:

8 0
2 years ago
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