1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
15

An alkane has molecular weight 86. Write its molecular formula. What will be its physical state?

Physics
1 answer:
Brums [2.3K]3 years ago
8 0

C6H14

Gaseous state

it's unsaturated hence gaseous

You might be interested in
What are two processes that result in rocks being broken down into smaller pieces ?
meriva
Mechanical and Chemical. (Weathering and erosion)
5 0
3 years ago
Read 2 more answers
Two rock climbers, bill and karen, use safety ropes of similar length. karen's rope is more elastic, called a dynamic rope by cl
Oliga [24]
You never gave us an answer, so therefore, we can't answer this question.
3 0
3 years ago
Read 2 more answers
It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80 × 10 7 J of energy whe
boyakko [2]

Answer:

10.4L of water is expended when 1L of crude oil is burned.

Explanation:

This problem requires us to calculate the volume of water that must be expended to absorb the amount of energy released from the burning of 1.00L of crude oil.

In going from water at 18.5°C to steam at 285°C, the water undergoes 3 stages:

Absorption of heat from 18.5°C to 100°C >> phase change to vapour at 100°C >> heating from 100°C to steam at 285°C

Given Cw = 4186 J/kg°C and Cs = 2020 J/kg°C. The latent heat of of vaporization of water Lv = 2.256 ×10⁶ J/kg

The total heat absorbed in the process per kilogram

H = Cw × (100 – 18.5) + Lv + Cs × (285 – 100)

H = 4186 × 81.5 + 2. 256 ×10⁶ + 2020× 185

= 2.696 ×10⁶ J/kg

The amount of heat in J/L of water needed can be calculated as follows:

Density of water = 1000kg/m³ =

1000 kg/m³ × 1m³/1000L = 1kg/L (Basically conversion of density in kg/m³ to kg/L)

Let the volume of water needed be V litres.

Then the mass of water that must be expended = Density × Volume

= 1kg/L × V L = Vkg

The heat that would be absorbed by the water when 1L of crude oil is burned is V×H

= 2.696×10⁶ × V

This is also equal to 2.80×10⁷ J of energy (given).

So,

2.696×10⁶V = 2.8×10⁷

V = (2.80×10⁷)/(2.696×10⁶) = 10.4L of water.

3 0
2 years ago
Read 2 more answers
you measured the torque caused by the gyroscope's weight by lifting up the end of the gyroscope (at 7.5 inches). If you measured
DIA [1.3K]

Answer:

i) No, the spring scale does not read a different value

ii) The torque will read a different value, it will reduce

iii) The spring scale does not need to be measured at the center of mass location.

Explanation:

The torque caused by the gyroscope can be given by the relation,

\tau = r × f

\tau = rf cos \theta

The torque measured by the gyroscope varies directly with the distance, r.

A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.

The weight of the gyroscope remains constant despite the reduction in the distance because the weight  of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.

Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.

3 0
3 years ago
The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent ho
faltersainse [42]

Answer:

Explanation:

Let mass of cylinder be M

Moment of inertia of cylinder

= 1/2 M R² r is radius of cylinder

If radius of equivalent  hoop be k

Mk² = 1/2 x MR²

k = R / √2

1.2 / 1.414

Radius of gyration = 0.848 m

b )

moment of inertia of spherical shell

= 2 / 3 M R²

Moment of inertia of equivalent hoop

Mk²

So

Mk² = 2 / 3 M R²

k = √2/3 x R

= .816 X 1.2

Radius of gyration = .98 m

c )

Moment of inertia of solid sphere

= 2/5 M R²

Moment of inertia of equivalent hoop

= Mk²

Mk² = 2/5 M R²

k √ 2/5 R

Radius of gyration = .63 R

6 0
3 years ago
Other questions:
  • Which answer choice?? I have trouble with this physics concept :/
    5·1 answer
  • What total mass must be converted into energy
    6·2 answers
  • Which of the following is not a property of displacement?
    7·2 answers
  • The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. W
    5·2 answers
  • 0. A 3.00-kg block is dropped from rest on a vertical spring whose spring constant is 750 N/m. The block hits the spring, compre
    11·1 answer
  • Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electr
    6·1 answer
  • Which property of sound waves decreases as the square of the distance from the source increases?
    12·2 answers
  • What is motion and explain also<br>​
    14·1 answer
  • Below is an oscilloscope trace from an AC supply. Calculate the frequency of the supply if each horizontal division represents 0
    11·1 answer
  • As shown in (Figure 1), a layer of water covers a slab of material X in a beaker. A ray of light traveling upwards follows the p
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!