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Natasha_Volkova [10]
2 years ago
11

Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles trave

led in a straight line and some were deflected at different angles.
Physics
1 answer:
jeyben [28]2 years ago
4 0

The question is incomplete, the complete question is;

Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles traveled in a straight line and some were deflected at different angles. Which statement best describes what Rutherford concluded from the motion of the particles? Some particles traveled through empty spaces between atoms and some particles were deflected by electrons. Some particles traveled through empty parts of the atom and some particles were deflected by electrons. Some particles traveled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms. Some particles traveled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.

Answer:

Some particles traveled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.

Explanation:

Rutherford first proposed the nuclear model of the atom after his landmark experiment.

In this experiment, alpha particles from a source was focused on a thin gold foil. Some of the particles passed through empty spaces within the atom but were deflected at different angles by a small area of high-density positive charge within an atom which Rutherford later called the atomic nucleus.

Hence the answer above.

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If the mess of an object______, the weight of an object will _______
Gnom [1K]

Answer:

the same

Explanation:

7 0
2 years ago
Where is the sun's energy most concentrated
Maru [420]

B. At the equator

Explanation:

The energy coming from the Sun hits the Earth's surface at different angles, depending on the latitude of the place. The more perpendicular the ray of lights hit the surface, the more the energy transmitted to the Earth's surface, the warmer the location.

The angle at which the ray of lights hit the Earth is related to the latitude: in particular, the ray of lights arrive perpendicular at the equator (0^{\circ}), they arrive at larger angle in the United States (which is located at intermediate latitudes) and they arrive at the largest angles at the poles. For this reason, the sun's most energy is concentrated at the equator.

5 0
2 years ago
An ideal gas occupies 0.4 m3 at an absolute pressure of 500 kPa. What is the absolute pressure if the volume changes to 0.9 m3 a
sveticcg [70]

Answer:

<h2>2.22 kPa</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{0.4 \times 500000}{0.9}   =  \frac{200000}{0.9} \\  = 222222.2222... \\  = 222222

We have the final answer as

<h3>2.22 kPa</h3>

Hope this helps you

5 0
2 years ago
Power plants release sulfur dioxide and nitrogen oxides into the atmosphere, where they combine with water vapor to form a. acid
Alla [95]
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6 0
3 years ago
Read 2 more answers
A cylindrical cistern, constructed below ground level, is 2.9 m in diameter and 2.0 m deep and is filled to the brim with a liqu
Tomtit [17]

Answer:

15.1 m

Explanation:

We first calculate the apparent depth from

refractive index, n = real depth/apparent depth

apparent depth, a  = real depth/refractive index

real depth = 2.0 m, refractive index = 1.4

apparent depth, a = 2.0/1.4 = 1.43 m

Since the cylindrical cistern has a diameter of 2.9 m, its radius is 2.9/2 = 1.45 m

The angle of refraction, r is thus gotten from the ratio

tan r = radius/apparent depth = 1.45/1.43 = 1.014

r = tan⁻¹(1.014) = 45.4°

The angle of incidence, i is gotten from n = sin i/sin r

sin i = nsin r = 1.4sin45.4° = 1.4 × 0.7120 = 0.9968

i = sin⁻¹(0.9968) = 85.44°

Since the girl's eyes are 1.2 m from the ground, the distance ,h from the edge of the cistern she must stand is gotten from

tan i = h/1.2

h = 1.2tan i = 1.2tan85.44° = 1.2 × 12.54 = 15.05 m

h = 15.05 m ≅ 15.1 m

So, she must stand 15.1 m away from the edge of the cistern to still see the object.

4 0
3 years ago
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