The total momentum of the system is 2.14i + 21.27j.
A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).
The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.
The total momentum of the system is defined as follows:
As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by
P = Pₓ + P'
where Pₓ is the x-component of momentum
P' is the y-component of the momentum
Also, we know that
P=mv
where m is mass
v is velocity
Thus,
P = Pₓ + P'
P = m₁vₓ + m₂v'
vₓ is the x-component of the velocity
v' is the y- component of the velocity
Given, m₁= 3.2kg
m₂ = 2.9kg
Now,
P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)
P = (7.36i + 13.44j) + (-5.22i + 7.83j)
P = 2.14i + 21.27j
Thus, the total momentum of the given system is 2.14i + 21.27j.
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