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Dafna11 [192]
3 years ago
8

radio signals travel at a rate of 3 x 10^8 meters per second. how many seconds will it take for a radio signal to travel from a

satellite to the surface of earth if the satellite is orbiting at a height of 3.6 x10^7 meters? Write the answer in scientific notation.
Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

time=1.2\times 10^{-1}\ second

Step-by-step explanation:

Given:

The speed of the radio is 3\times 10^{8} meters per second.

The distance of the satellite from the earth is 3.6\times 10^{7} meter

The formula of the speed is

speed = \frac{distance}{time}

For time the formula is.

time = \frac{distance}{speed}

put distance and speed value in above equation.

time = \frac{3.6\times 10^{7}}{3\times 10^{8}}

time = \frac{1.2 x 10^{7}}{10^{8}}

time=1.2\times 10^{7}\times 10^{-8}

time=1.2\times 10^{7-8}

time=1.2\times 10^{-1}\ second

Therefore, the radio will be take the time is 1.2\times 10^{-1}\ second or 0.12 seconds.

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