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3 years ago

8

radio signals travel at a rate of 3 x 10^8 meters per second. how many seconds will it take for a radio signal to travel from a

satellite to the surface of earth if the satellite is orbiting at a height of 3.6 x10^7 meters? Write the answer in scientific notation.

1 answer:

zvonat [6]3 years ago

6 0

Answer:

$time=1.2\times 10^{-1}\ second$

Step-by-step explanation:

Given:

The speed of the radio is $3\times 10^{8}$ meters per second.

The distance of the satellite from the earth is $3.6\times 10^{7}$ meter

The formula of the speed is

$speed = \frac{distance}{time}$

For time the formula is.

$time = \frac{distance}{speed}$

put distance and speed value in above equation.

$time = \frac{3.6\times 10^{7}}{3\times 10^{8}}$

$time = \frac{1.2 x 10^{7}}{10^{8}}$

$time=1.2\times 10^{7}\times 10^{-8}$

$time=1.2\times 10^{7-8}$

$time=1.2\times 10^{-1}\ second$

Therefore, the radio will be take the time is $1.2\times 10^{-1}\ second$ or 0.12 seconds.

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