Answer: Babe Ruth got 47 singles in the 1918 season.
Step-by-step explanation:
Outcomes for base hits. = singles, doubles , triples , home runs
Now , the number of singles = Number of base hits - Number of doubles - Number of triples - Number of home runs
Given : Babe Ruth had 26 doubles, 11 triples, and 11 home runs out of 95 base hits.
Number of singles = 95-26-11-11
= 95 - 48
= 47
Hence, Babe Ruth got 47 singles in the 1918 season.
