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3 years ago

What is the inverse of f(x)=2(x+4)²-5

Mathematics

1 answer:

olchik [2.2K]3 years ago

3 0

I would be <em> $2x^{2} +16x+27$ </em>

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Does the table represent y as a function of x? (Please explain answer as to how you got it)

Illusion [34]

Answer:

Step-by-step explanation:

The table represents two sets of data

The values of x are repeated (3.45 appears twice)

Therefore it not a function as per definition of a function

The answer is no

5 0

3 years ago

(Inscribed Angles)<br> Find m

mote1985 [20]

The answer will be Mx+b

3 0

4 years ago

Omar was paid on Friday. On Saturday he spent 1/4 of his pay and on Sunday he bought a new smartphone with 2/3 of the remainder.

nasty-shy [4]

Answer:

Friday: 300 dollars

Step-by-step explanation:

Let Omar's pay on Friday = x

Friday: x

Saturday: 1/4 x was spent.

Sunday: 2/3 *(x - (1/4)x ) = 2/3 * (3/4x) = (2*3/(3*4)x = (6/12)x = 1/2x

Dinner: 15 dollars

Remainder = 20% x = 20/100 x = 0.2x

x - (1/4x + 1/2(x) + 15) = 0.2x Combine like terms on the left

x - (3/4x + 15) = 0.2x Remove the brackets

x - (3/4)x - 15 = 0.2x Combine like terms on the left

(1/4)x - 15 = 0.2x Change 1/4 to a decimal

0.25x - 15 = 0.2x Subtract 0.25x from both sides

0.25x - 0.25x - 15 = 0.2x - 0.25x Combine

- 15 = - 0.05x Divide by - 0.05

-15 /-0.05 = - 0.05 x/ 0.05

300 = x

3 0

4 years ago

Ace Truck leases its 10-ft box truck at $30/day and $0.50/mi, whereas Acme Truck leases a similar truck at $25/day and $0.55/mi.

scoray [572]

Answer:

Ace Truck

$C(m) = 30 + 0.5*m$

Acme Truck

$C(m) = 25 + 0.55*m$

Step-by-step explanation:

The cost function to lease a box truck from a company has the following format:

$C(m) = F + a*m$

In which F is the fixed cost and a is the cost per mile m.

(a) Find the daily cost of leasing from each company as a function of the number of miles driven.

Ace Truck

$30/day and $0.50/mi. This means that $F = 30, a = 0.50$ . So

$C(m) = 30 + 0.5*m$

Acme Truck

$25/day and $0.55/mi. This means that $F = 25 a = 0.55$ . So

$C(m) = 25 + 0.55*m$

8 0

3 years ago

Help with this pleaseee

Savatey [412]

Answer:

Sum of 100 terms of the sequence = 15050

Step-by-step explanation:

Given expression which represents a sequence is,

$\sum_{r=1}^{100}(3r-1)$

So the sequence will be,

2, 5, 8, 11, 14..........

So, the given sequence is an arithmetic sequence with,

First term of the sequence 'a' = 2

Common difference 'd' = 5 - 2 = 3

Sum of 'n' terms of an arithmetic sequence is given by,

$S_n=\frac{n}{2}[2a+(n-1)d]$

Here, n = number of terms

a = first term

d = common difference

$S_{100}$ = $\frac{100}{2}[2(2)+(100-1)(3)]$

= 50[4 + 297]

= 15050

Therefore, sum of 100 terms of the sequence = 15050

3 0

3 years ago