All categories

3 years ago

The cost in dollars for removing p percent of pollutants from a river in Smith County is?

2 answers:

5 0

Ok lets go ahead and see if the following answers can help:
A) if p = 0.2 then C(p) = 157.52
B) if p = 0.95 then C(p) = 753.86
C) smallest p value that gives C(p) > or = 0. This is p = 0
D) largest INTEGER value for C(p) to exist or be >=0. This is p = 99. p = 100 gives 786000/0; does not exist. p > 101 starts giving negative numbers.
I hope this has been of help

slamgirl [31]3 years ago

3 0

Answer:

1. The cost of removing 20% of pollutants is $19,650

2. The cost of removing 95% of pollutants is $1,493,400

3. Smallest value of p can be 0

4. Largest value of p can be 99

Step-by-step explanation:

The equation is $C(p)=\frac{78,600p}{100-p}$

Where,

C(p) is the cost, and
p is the percent of pollutants

Find the cost of removing 20%.

We simply plug in 20 into p in the formula and get:

$C(p)=\frac{78,600(20)}{100-20}=19,650$

The cost of removing 20% of pollutants is $19,650

Find the cost of removing all but 5% of the pollutants.

This basically translates to removing 100-5=95%, so we simply plug in 95 into p int he formula and get:

$C(p)=\frac{78,600(95)}{100-95}=1,493,400$

The cost of removing 95% of pollutants is $1,493,400

What is the smallest value p can be?

We can opt to clean nothing, so p can be zero (0). p is the percent of pollutant to clean, so if we decide not to clean, then p can be 0. Hence, the smallest value of p is 0.

What is the largest integer value p can be?

Percent of pollutants to clean would be 100% (theoretically). But this would violate laws of arithmetic. Because if we were to use 100 in the formula, there would be division by 0, which isn't permitted. So the closest largest integer below 100 is 99. So the largest integer value of p is 99. (anything over 100 doesn't make sense and is not feasible)

You might be interested in

3 l = _____ dl A. 0.3 B. 0.03 C. 300 D. 30

Andru [333]

Answer: The correct option is D, i.e.,30.

Explanation:

It the given equation we have two units l and dl.

Where l represents the liter and dl represents the deciliter. These are the volume units.

We know that,

1 liter = 10 deciliter

It means,

1 l = 10 dl

Multiply both sides by 3,

1\times 3 l = 10\times 3 dl

3 l = 30 dl

Therefore, the correct option is D and 3 l = 30 dl.

6 0

3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

How can you make 64, multiplying just two numbers?

Darina [25.2K]

These are all the answers to this question!

1 x 64 = 64

2 x 32 = 64

4 x 16 = 64

8 x 8 = 64

16 x 4 = 64

32 x 2 = 64

64 x 1 = 64

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +

34kurt

Answer:

$36i^{2}+48i+16$

Step-by-step explanation:

$(4+6i)^{2}$ is essentially $(4+6i)(4+6i)$ (you are squaring $(4+6i)$ , so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

$(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$

( $(4*4)+(4*6i)+(6i*4)(6i*6i)$ )

After doing so, you would end up with $16+24i+24i+36i^{2}$ , and after combining like terms, $16+48i+36i^{2}$ .

To write the expression in standard form, though, just order the terms from highest to lowest power!

5 0

3 years ago

1.13 Thank you! (Sorry it’s so blurry)

VikaD [51]

$\sqrt[8]{48^4}$ can be rewritten as $48^4$ to the $\frac{1}{8}$ power:

$(48^4)^ \frac{1}{8}$

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

$(48^ \frac{1}{2})$

This is equivalent to $\sqrt{48}$ , so now, we just simplify:

$\sqrt{48}= \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}$

So:

$\sqrt[8]{48^4} =4 \sqrt{3}$

4 0

4 years ago