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Liula [17]
4 years ago
13

Type your response in the box.

Physics
2 answers:
SVEN [57.7K]4 years ago
5 0

With the passage of time, the rock wall would be weathered under the impact of flowing water and would receede backwards.

Explanation:

Given details=

Water flowing at the pace of 2 to 3 feet per sec

It must be understood that flowing water act as an erosive agent here.

As the water flows, it carries with itself erosive tools which erode the rock surface. Since the speed of water is considerable, the erosion is quite significant. Due to the erosive action of the river, the rock wall would be continuously eroded starting from the tip and in turn, would recede backwards (in the upstream direction).

lidiya [134]4 years ago
4 0

Sample Answer:

The water will weaken the rock wall. Therefore, the wall will gradually crumble or wear away.

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A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether
White raven [17]

Answer:

a) 51.8 cm³

b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.

Explanation:

a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)

V = 1000/19.3

V = 51.8 cm³

7 0
3 years ago
What is the efficiency (w/qh) of an ideal carnot heat engine operating between a hot region at t= 400 k and a cold one at t= 300
Vinvika [58]
The efficiency of an ideal Carnot heat engine can be written as:
\eta = 1-  \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the temperature of the cold region
T_{hot} is the temperature of the hot region

For the engine in our problem, we have T_{cold}=300 K and T_{hot}=400 K, so the efficiency is
\eta= 1 - \frac{300 K}{400 K}=0.25
4 0
3 years ago
Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose th
mario62 [17]

Answer:25.61 m/s

Explanation:

Given

truck is moving eastbound with a velocity of 16 m/s

Velocity of truck v_t=16\hat{i}

SUV is moving south with a velocity of 20 m/s

Velocity of SUV in vector form v_s=-20\hat{j}

Velocity of truck relative to the SUV

v_{ts}=v_{t}-v_s

v_{ts}=16\hat{i}-(-20\hat{j})

Magnitude of relative velocity is

|v_{ts}|=\sqrt{16^2+20^2}

|v_{ts}|=25.61\ m/s                                                  

5 0
3 years ago
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lawyer [7]

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4 years ago
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Andreyy89

Answer:do when the what or them yea cause oh?

Explanation:

8 0
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