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Lyrx [107]
3 years ago
8

body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N. Wh

at is the tension in each wire?
Physics
1 answer:
steposvetlana [31]3 years ago
3 0
<span>The wires are suspended diagonally, meaning the tension in each is directed diagonally as well (along the wire). We can, however, talk about the horizontal and vertical components of the tension force. The horizontal tension force in each wire is Tcosθ, while the vertical tension force is Tsinθ. The horizontal tension forces balance one another, because the wires are pulling in opposite directions. This means Tcosθ=Tcosθ, which is obvious but not very helpful. If you look at the vertical tension forces on the other hand, you can see that they must balance the weight of the body for the system to be in equilibrium. In other words: Tsinθ+Tsinθ=mg You're given enough information in the question to solve for T using this equation!</span>
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An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
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Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

Applying Gauss' law:

Electric Field E = Charge density/epsilon nought

Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

How far the electron would travel S =ut+ at^2/2 where u=0

S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

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» Force is 200,000 Newtons

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{ \tt{force =  \frac{impulse}{time} }} \\  \\ { \tt{force =  \frac{20000}{0.1} }} \\  \\ { \tt{force = 200000 \: newtons}}

8 0
2 years ago
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I think is between A&B
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