Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) = 
- 
⇒ x + iy = 
⇒ x + iy = 
[ ∵ 
]
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Answer:
Step-by-step explanation:
you will need to do:
j/9*2=2j/9
Answer:
Step-by-step explanation:
Hello,
First of all we will take any real number x different from 0, -2, +2 as dividing by 0 is not allowed and then we can write
because we know that
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Use the z-score:
112 - 100
For 112, the z-score is --------------- = 12/15, or 0.8.
15
Next, find the AREA under the standard normal curve TO THE LEFT OF 0.8.
Use either a z-score table or a calculator for this purpose.
Using my calculator, I found that this area is 0.532. That places 112 in the 53rd percentile.
82 would be in a lower percentile: the 12th percentile.
Let me know if you have questions about how to use a calculator to do these calculations.
Answer:
Step-by-step explanation:
1. P = (width + lengh) * 2 = (23 + 10) * 2 = 33 * 2 = 66
A = width * lengh = 23 * 10 = 230
2. width = 7
P = (width + lengh) * 2 = ( 7 + 9) * 2 = 16 * 2 = 32
