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serious [3.7K]
2 years ago
9

Mai wants to construct a regular hexagon inscribed in the circle centered at C. Will these instructions work to finish the hexag

on from the construction given? If so, explain why Mai is correct. If not, explain how you would finish the construction correctly.
i. Draw the circle centered at D with radius CD.
ii. Mark the intersection of the circle with the circle centered at C, and label that point E.
iii. Draw the circle centered at E with radius DE.
iv. Mark the intersection of the circle with the circle centered at D, and label that point F.
v. Connect ABCDEF to make a regular hexagon.​
Mathematics
1 answer:
VARVARA [1.3K]2 years ago
6 0

Answer:

Place your compass point on the paper and draw a circle. (Keep this compass span!)

2. Place a dot, labeled P, anywhere on the circumference of the circle to act as a starting point.

3. Without changing the span on the compass, place the compass point on P and swing a small arc crossing the circumference of the circle.

4. Without changing the span on the compass, move the compass point to the intersection of the previous arc and the circumference and make another small arc on the circumference of the circle.

5. Keep repeating this process of "stepping" around the circle until you return to point P.

6. Starting at P, connect to each arc on the circle forming the regular hexagon.

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The coordinates of the vertices of quadrilateral DEFG are D(−2, 5) , E(2, 4) , F(0, 0) , and G(−4, 1) .
daser333 [38]

Answer: The correct option is a.Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.

Explanation:

It is given that  coordinates of the vertices of quadrilateral DEFG are D(−2, 5) , E(2, 4) , F(0, 0) , and G(−4, 1) .

The distance formula for two points is given below,

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

DE=\sqrt{(2+2)^2+(4-5)^2}=\sqrt{17}

EF=\sqrt{(0-2)^2+(0-4)^2}=\sqrt{20}

FG=\sqrt{(-4-0)^2+(1-0)^2}=\sqrt{17}

DG=\sqrt{(-4+2)^2+(1-5)^2}=\sqrt{20}

Slope formula,

m=\frac{y_2-y_1}{x_2-x_1}

Slope of DE,

m_1=\frac{4-5}{2+2}= \frac{-1}{4}

Slope of EF,

m_2=\frac{0-4}{0-2}= 2

Slope of FG,

m_3=\frac{1-0}{-4-0}= \frac{-1}{4}

Slope of DG,

m_4=\frac{1-5}{-4+2}= 2

The slope of opposite sides are equal, it means the opposite sides are parallel.

All four sides do not have the same length. It means it is not a rhombus.

From the figure it is noticed that the opposite sides are parallel.

Therefore, the correct option is a.Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.

3 0
3 years ago
Read 2 more answers
The manager at Gabriel's Furniture Store is trying to figure out how much to charge for a bookshelf that just arrived. The books
melomori [17]

First: markup rate × wholesale price = amount of markup

Second: Well the markup rate is a percentage, you have to convert it into a decimal. Percent means "out of one hundred," so <span>80%</span> is equivalent to <span>80/100 </span>which is also equal to <span>80÷100</span>.

<span>Third: 80÷100=0.80</span>

0.80 × $93.00 = $74.40

Fourth: The markup rate is a percentage of the wholesale price that is added to get the retail price, you can find the retail price with the following equation: amount of markup + wholesale price = retail price

<span>$74.40</span> + <span>$93.00</span> = <span>$167.40</span>

The retail price of the chair should be <span>$167.40</span>.

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3 years ago
Solve the blank: This equation for this graph is y=____x + _______​
Marysya12 [62]

Answer:

y=3x+2

Step-by-step explanation:

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3 years ago
I need help understanding how to do this problem (image attached).
ikadub [295]
Well to find the value of the interior angle of a hexagon it would be out of a total of 720 degrees therefore just subtract the values of the known interior angle values and you should be able to get the value of the interior angle of X
4 0
3 years ago
BRAINLIEST ANSWERS ONLY.
mars1129 [50]

Answer:

Heyy

Step-by-step explanation:

△ABC is a right angled triangle and right angle at B

sinA=

AC

BC

, cosA=

AC

AB

⟹sinA+cosA=

AC

BC

+

AC

AB

=

AC

BC+AB

[We know that sum of two sides of a triangle is greater than the third side]

⟹sinA+cosA>

AC

AC

=1

Hence, sinA+cosA>1

4 0
2 years ago
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