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ivolga24 [154]
3 years ago
10

Factor completely. 2x^2y + 2xy + 4x + 4 A. (2x + 4)(xy + 1) B. (2x + 4y)(x + 1) C. 2(xy + 2)(x + 1) D. (2xy + 4)(x + 1)

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

2(xy + 2)(x + 1)   (C)

Step-by-step explanation:

2x^2y + 2xy + 4x + 4

= 2xy(x + 1) + 4(x + 1)

= (2xy + 4)(x + 1)

=  2(xy + 2)(x + 1)

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Then by Baye's Theorem,

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