we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer: try to (x) each one by the answer to -0.0035 +70
Step-by-step explanation:
Answer:
x= −41
/20
Step-by-step explanation:
(2x+3)(2)+8(2x+3)+11=0
(4x+16x)+(6+24+11)=0(Combine Like Terms)
20x+41=0
20x+41=0
Step 2: Subtract 41 from both sides.
20x+41−41=0−41
20x=−41
Step 3: Divide both sides by 20.
20x
/20 = −41
/20
x=
−41
/20
multiply 20 by 500. it should help you with the problem.