<span>During complete combustion, the hydrocarbon reacts with oxygen (O2) to from carbon dioxide (CO2) and water (H2O). For the combustion of one molecule of octane, 8 molecules of CO2 and 9 molecules of H2O must be formed to account for all the atoms of carbon and hydrogen in the octane. This requires 25 atoms of oxygen, or 12.5 molecules of O2:
C8H18+12.5*O2=9*H2O+8*CO2
Multiply both sides by 2 to obtain whole number coefficients:
2*C8H18+25*O2=18*H2O+16*CO2
The coefficient of carbon dioxide in the balanced equation is 16.</span>
Answer:
2.50 atm
Explanation:
We have 10.4 g of DDT (solute), whose molar mass is 354.50 g/mol. The corresponding moles are:
10.4 g × (1 mol/354.50 g) = 0.0293 mol
The molarity of the solution is:
M = moles of solute / liters of solution
M = 0.0293 mol / 0.286 L
M = 0.102 M
We can find the osmotic pressure (π) using the following pressure.
π = M × R × T
where,
R: ideal gas constant
T: absolute temperature
π = M × R × T
π = 0.102 M × 0.0821 atm.L/mol.K × 298 K
π = 2.50 atm
Answer:
0.004395
Explanation:
do u mean in scientific if u do this is the answer
Answer: C) 0.020 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in g
Mole fraction of 
is = 
i.e. moles of is present in 1 mole of solution.
Moles of solute 
=
moles of solvent (water) = 1 - = 0.99
weight of solvent =
Molality =
Thus approximate molality of in this solution is 0.020 m
Answer:
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
Step 1: Data given
Nitric acid = HNO3
Molar mass of H = 1.01 g/mol
Molar mass of N = 14.0 g/mol
Molar mass O = 16.0 g/mol
Number of moles nitric acid (HNO3) = 0.25 moles
Molairty = 0.10 M
Step 2: Calculate molar mass of nitric acid
Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)
Molar mass HNO3 = 1.01 + 14.0 + 3*16.0
Molar mass HNO3 = 63.01 g/mol
Step 3: Calculate mass of solute use
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.25 moles * 63.01 g/mol
Mass HNO3 = 15.75 grams
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
