1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garri49 [273]
3 years ago
11

0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. How many grams of solute was used?

Chemistry
1 answer:
Yanka [14]3 years ago
7 0

Answer:

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

Explanation:

Step 1: Data given

Nitric acid = HNO3

Molar mass of H = 1.01 g/mol

Molar mass of N = 14.0 g/mol

Molar mass O = 16.0 g/mol

Number of moles nitric acid (HNO3) = 0.25 moles

Molairty = 0.10 M

Step 2: Calculate molar mass of nitric acid

Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)

Molar mass HNO3 = 1.01 + 14.0 + 3*16.0

Molar mass HNO3 = 63.01 g/mol

Step 3: Calculate mass of solute use

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.25 moles * 63.01 g/mol

Mass HNO3 = 15.75 grams

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

You might be interested in
Calculate the mass of beryllium (Be) needed to completely react with 18.9 g nitrogen gas (N2) to produce Bez N2, which is the on
choli [55]

Answer:

C = 18.29 g  

Explanation:

Given data:

Mass of beryllium needed = ?

Mass of nitrogen = 18.9 g

Solution:

Chemical equation:

3Be + N₂    →    Be₃N₂

now we will calculate the number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 18.9 g/ 28 g/mol

Number of moles = 0.675 mol

Now we will compare the moles of nitrogen and Be from balance chemical equation.

                     N₂        :       Be        

                       1          :       3

                  0.675       :      3/1×0.675 = 2.03 mol

Number of moles of Be needed are 2.03 mol.

Mass of Beryllium:

Mass = number of moles × molar mass

Mass = 2.03 mol ×   9.01 g/mol

Mass = 18.29 g  

4 0
3 years ago
What are mountins ussaly made from
Katarina [22]

Answer:

rocks and earth

Explanation:

hope this helps

5 0
3 years ago
Read 2 more answers
The majority of Canada’s manufacturing takes place in the provinces of Ontario and __________.
nikklg [1K]
C. Quebec hope this helps :)
6 0
2 years ago
Read 2 more answers
The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below. Cu + 2AgNO3 2Ag + Cu(N
Luden [163]
1 mol Cu - 2 mol Ag
x             - 0.854 mol Ag

x=0.854*1/2=0.427 

0.427 mol Cu
5 0
3 years ago
Read 2 more answers
You see a solid that looks like an ice cube, but it does not melt at room temperature. Can the solid be frozen water? Explain.
12345 [234]
No, the solid can not be frozen water. This is because water has a melting point of 32 degrees Fahrenheit. Room temperature is well above 32 degrees, so the solid would have begun to melt. Since the solid was not melting, we can infer that it is not water.  
8 0
3 years ago
Read 2 more answers
Other questions:
  • For the closed system below: Cu(s) + 2Ag+(aq) 2Ag(s) + Cu2+(aq) How would you know if the system is at equilibrium?
    15·2 answers
  • Which of the following are weak electrolytes in water
    5·2 answers
  • Water is being pumped from the bottom of a well 150 feet deep at a rate of 200 gal/hour into a vented storage tank 30 feet above
    7·1 answer
  • _______ rock is formed when debris is buried, compressed and cemented together.
    6·1 answer
  • A balloon at 32 °C is filled with 21 L of air. What would its volume be at a temperature of 52 °C, assuming pressure remains con
    5·1 answer
  • What is the definition of a Lewis acid?
    14·1 answer
  • How is ozone produced?
    8·2 answers
  • PLS ANSWER THANK YOUU
    7·1 answer
  • Which medical condition(s) can prevent molecules from entering the cell?
    15·2 answers
  • _ S8 +_02 +_ SO3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!