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andrew11 [14]
3 years ago
12

I need to show my work, could anyone help? (need by tonight 3/10/20

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

14 gallons....$42

Step-by-step explanation:

The car requires one gallon every 32 miles...

The car requires c gallons for 448 miles

c = 448 × 1 / 32

= 14 gallons..

One gallon = $3

Fourteen gallons = ??

14 × 3 / 1 = $42

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Do 9/32. 32 is the total
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6 0
3 years ago
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Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Which system below has no solution?
Alex787 [66]

Answer:

Step-by-step explanation:

A system has no solution if the 2 (or more) functions that make up the system do not intersect.  The only pair of functions here that do not have an intersection is found in D. You could graph these 2 on a graphing calculator to see that this is true.

4 0
3 years ago
Suppose that y varies directly with x and y=12 when x=-2. what is when x=-6?
dlinn [17]
Y=4

How?
When they say directly you should multiply the x and y together. You would get -24, now using that number divide -24 by the new x(-6) you would get 4.
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