<span>%Antifreeze=<span><span>V<span>Antifreeze</span></span><span>V<span>Fluid</span></span></span></span>
<span><span>V<span>Fluid</span></span>=<span><span>V<span>Antifreeze</span></span><span>%Antifreeze</span></span></span>
<span><span>V<span>Antifreeze</span></span>=<span>V<span>fluid</span></span>∗%Antifreeze</span>
I want to find the amount of antifreeze in a 15 quart solution with 30% antifreeze
<span><span>V<span>Antifreeze</span></span>=15∗0.30</span> =18/4 quarts of antifreeze
Similarly, I want to find the amount of antifreeze in a 15 quart solution with 35% antifreeze first.
<span><span>V<span>Antifreeze</span></span>=15∗0.35</span> = 21/4 quarts of antifreeze
<span>the difference between 21/4 and 18/4 is 3/4 quarts, which is the amount of pure antifreeze I've added in.
</span><span>
SO the V_fluid I replaced with 3/4 quarts of antifreeze is (3/4)/ 0.35</span>
<span>we are given with a swimming pool with dimensions
</span>12-ft-by-15-ft. given that there is a <span>3-ft-wide no-slip surface around it, the new dimensions now become (12+3+3) or 18 ft by (15+3+3) or equal to 21 ft. The perimeter is the sum of the sides of the new rectangle. Perimeter is equal to 18+ 18 + 21 + 21 or equal to 78 feet</span>
To create this inequality graph, you will have an open circle at 50 and an arrow pointing to the right.
Since the bag must be over 50, we draw an open circle at fifty.
Since the fee goes towards the bags over 50, we draw an arrow pointing to the right.
Cost of the admission tickets: 11.75x
Cost of the box lunch: 5x
Expressions to find the total cost = (1) ....... 11.75x + 5x
That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.
Now calculate the cost for x = 5 using both expressions:
1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75
2) 16.75(5) = 83.75
Of course you got the same result with both expressions.
#1
n^32 (2nd choice)
#2
1/x^15 (1st choice)
#3
c^15 (2nd choice)
#4
x^10 / m^3 (last choice)
#5
x^12y^8 (1st choice)
#6
1 / 8y^12 (3rd choice)
#7
r^10 s^5 (last choice)
#8
x^4 / y^6 (last choice)
#9
(b^2)^4 = b^8
answer is 4 (2nd choice)
