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Monica [59]
4 years ago
13

What is 3/8 times -1/3

Mathematics
2 answers:
larisa [96]4 years ago
7 0
3 x -1 = -3
8 x 3 = 24
-3/24 = -1/8
-1/8, Hope this helps!
Zinaida [17]4 years ago
3 0

\frac{3}{8}  \times  -  \frac{1}{3}
3 on bottom cancels out 3 on top, so answer is: -1/8
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What is the magnitude of the position vector whose terminal point is (6, -4)?
Marysya12 [62]

Answer:

  2√13

Step-by-step explanation:

The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...

  d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)

  = √(36 +16) = √52 = √(4·13)

  d = 2√13 = |(6, -4)|

5 0
3 years ago
Find the length of the third side to the nearest tenth.<br> 8<br> 5
brilliants [131]

Answer:

The length of third side is: 6.3

Step-by-step explanation:

Given triangle is a right triangle where

Base = ?

Perpendicular = 5

Hypotenuse = 8

Let x be the base

As it is a right-angled triangle, Pythagoras theorem can be used to find the third side

Hypotenuse^2 = Base^2 + Perpendicular^2

Putting the known values

(8)^2 = x^2 + (5)^2\\x^2 = (8)^2-(5)^2\\x^2 = 64-25\\x^2 = 39\\

Taking square root on both sides

\sqrt{x^2} = \sqrt{39}\\x = 6.24499

Rounding off to the nearest 10th

Base = 6.3

Hence,

The length of third side is: 6.3

6 0
3 years ago
2 *p2 + 3s for p = 3 and s = 11
maw [93]

Answer:

51

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out equation

2p² + 3s

Step 2: Define variables

<em>p</em> = 3

<em>s</em> = 11

Step 3: Replace variables

2(3)² + 3(11)

Step 4: Evaluate

2(9) + 33

18 + 33

51

8 0
4 years ago
A building is 30 feet high. At a distance away from the building, an observer notices that the angle of elevation to the top of
yKpoI14uk [10]

Answer

As per the statement:

Height of the building(h)= 30 feet

Angle of elevation (\theta)= 41°

We have to find the distance of observer from the base of the building.

Using tangent ratio:

\tan \theta= \frac{\text{Opposite side}}{\text{Adjacent side}}

You can see the diagram as shown below.

Opposite side = height of the building = 30 feet.

Adjacent side = distance of observer from the base of the building = x (let)

Then;

\tan 41^{\circ}= \frac{30}{x}

0.86928673781 = \frac{30}{x}

By cross multiply we have;

0.86928673781x = 30

Divide by 0.86928673781 both sides we get;

x = 34.51 m

Therefore, the distance of observer from the base of the building is 34.51 m


7 0
3 years ago
This is algebra 1<br> find the range and domain
s2008m [1.1K]

Answer:

Range: {2,3,4,5,7}

Domain: { 2,3,8,10,14}

I have answered have a good day.

4 0
3 years ago
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