Answer:
We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.
We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :
1 - We first group terms with the same variable :
(x²+8x) + (y²+22y) + 37 = 0
2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)
(x²+8x) + (y²+22y) = - 37
3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.
x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²
y²+22y = (y²+22y+11²)-11² = (y+11)²-11²
4 - We plug the new values inside our equation :
(x+4)² - 4² + (y+22)² - 11² = -37
(x+4)² + (y+22)² = -37+4²+11²
(x+4)²+(y+22)² = 100
5 - We re-write in standard form :
(x-(-4)²)² + (y - (-22))² = 10²
And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)
I have This too sooo hard
1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5
Answer:
x = 7, y = 6
Step-by-step explanation:
solve for y for the first equation
2x + y = 20
-2x -2x , eliminate 2x
y = 20-2x
now that we have found y, substitute the y in for the second equation
-5y = -6x + 12
-5(20-2x) = -6x + 12, we just changed y into 20-2x. remember that we are multiplying all of 20 - 2x by -5
-100+10x = -6x + 12, we multiplied everything from the parathesis by -5
+100 + 100, eliminate -100
10x = -6x + 112
+6x +6x , eliminate 6x
16x = 112 , solve for x
x = 7
then y = 20 - 2x = 20 - 2*7 = 6
check:
2 * 7 + 6 = 20
20 = 20
-5 * 6 = -6 * 7 + 12
-30 = -42 + 12
-30 = -30
Answer:
Kelvin wrote 60 the wrong way.
He has to write $30.65 - 60%, not 0.60.
Here is the final correct equation:
$30.65 - 60% = 12.26