Substitute
, so that
. Then the ODE is equivalent to

which is separable as

Split the left side into partial fractions,

so that integrating both sides is trivial and we get








Given the initial condition
, we find

so that the ODE has the particular solution,

Answer:
4 packages
Step-by-step explanation:
Since the store sells by 1/2 packages, we have to round 1.72 UP to 2.00. Then we multiply 1/2pound by 4= 2.00 pounds
Answer:
Step-by-step explanation:
b + 2 = b + 2
Answer:
$15
Step-by-step explanation:
The original price of the mirror is unknown, so let's call it x.
The discount on the original price is a 20% discount, so it is 20% of x, or 0.2x.
We are told the discount is $3, so 0.2x = 3. Now we solve the equation for x.
0.2x = 3
Divide both sides by 0.2.
x = 3/0.2
x = 15
The regular price is $15.
Answer:
-3/2
Step-by-step explanation:
The slope is found by
m = ( y2-y1)/(x2-x1)
Using the points (-4,11) and ( 0,5)
m = ( 11-5)/( -4-0)
= 6/-4
= -3/2