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3 years ago

The tThe term 10x3y2 is a term in which binomial expansion?

Mathematics

1 answer:

MAXImum [283]3 years ago

6 0

Answer:

(x + y)^5.

Step-by-step explanation:

The (r+1)th term of (x + y)^n = nCr x^n-r y^r

Compare this with 10x^3 y^2 we get

nCr = 10 , n-r = 3 and r = 2 giving n = 3+2 = 5

5C2 = 10.

So the answer is (x + y)^5.

You might be interested in

What is the area of circle? Show work !!!

Serjik [45]

Answer:

=615.44 m^2

Step-by-step explanation:

The area of the circle is given by

A = pi r^2

= pi (14)^2

= (3.14) 14^2

=615.44 m^2

6 0

3 years ago

What is X in the equation -15x+15(-4)=-30

love history [14]

<em><u>Answer: x=-2 *The answer should be the negative sign.*</u></em>

Step-by-step explanation:

distributive property: a(b+c)=ab+ac

remove parenthesis

-15x-15*4=-30

15*4=60

-15x-60=-30

add 60 both sides of an equation.

-15x-60+60=-30+60

simplify.

-15x=30

divide by -15 both sides of an equation.

-15x/-15=30/-15

simplify.

30/15=2

x=-2

Hope this helps!

Thanks!

Have a great day!

7 0

3 years ago

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

The cost of 2 kg of onions is ₹24. What will the cost of 12 kg of onions be?

max2010maxim [7]

Answer:

144 rupees

Step-by-step explanation:

2 kg= 24 rupees

2/2 kg= 24/2 rupees

1 kg= 12 rupees

1×12 kg= 12×12 rupees

12 kg= 144 rupees

8 0

3 years ago

Question 2

Masteriza [31]

1.1, 0.10299, 0.1038, 0.9 im pretty sure

6 0

3 years ago