G (x) = x + 1 (fog) (x) = x 2 + 3x + 1 ⇒ (fog) (x) = x 2 + 3x + 1 ⇒ f (g (x)) = x 2 + 3x + 1 ⇒ f (x + 1) = x 2 + 3x + 1 Eg x + 1 = p, then x = p - 1. ⇒ f (p) = (p - 1) 2 + 3 ( p - 1) + 1 ⇒ f (p) = p 2 - 2p + 1 + 3p - 3 + 1 ⇒ f (p) = p 2 + p - 1 So f (x) = x 2 + x - 1 - ->
ANSWER IS : x 2 + x - 1
Answer:
-40+44i
Step-by-step explanation:
4(-10+11i) = -40+44i
hope its clear
Answer:
Factor the numerator and denominator and cancel out the common factors.
x
^2
−
3 is your final answer.
Step-by-step explanation:
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Answer:
The value of annuity is 
Step-by-step explanation:
From the question we are told that
The periodic payment is 
The interest rate is 
Frequency at which it occurs in a year is n = 4 (quarterly )
The number of years is 
The value of the annuity is mathematically represented as
(reference EDUCBA website)
substituting values
![P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20250%20%2A%20%20%5B1%20%20-%20%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%5E%7B-10%20%2A%204%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%7D%7B%20%5Cfrac%7B0.08%7D%7B4%7D%20%7D%20%5D)
![P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B1%20%20-%20%281.0125%20%29%5E%7B-40%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%20%29%7D%7B0.0125%7D%20%5D)
![P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B0.3916%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%29%7D%7B0.0125%7D%20%5D)

She pays 9.6 euros. Hope this helped, could I possibly get brainliest?