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Trava [24]
3 years ago
13

Plzzz help me I am timed plz

Mathematics
1 answer:
myrzilka [38]3 years ago
8 0

Answer:

The first option

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Whats the ninth term of 25 20 15 10 5
Kaylis [27]

Given:

The sequence is 25, 20, 15, 10, 5.

To find:

The ninth term of the given sequence.

Solution:

We have,

25, 20, 15, 10, 5

It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

                                       = -5

The nth terms of an AP is

a_n=a+(n-1)d

Where, a is the first term and d is the common difference.

Putting a=25, n=9 and d=-5 to get the 9th term.

a_9=25+(9-1)(-5)

a_9=25+(8)(-5)

a_9=25-40

a_9=-15

Therefore, the ninth term of the given sequence is -15.

3 0
3 years ago
6. Circle all the expressions that are equivalent to this expression: 6p+ 7.
-BARSIC- [3]
Number 4 and 6 are correct because you can only add variables with other variables so that is why 4 and 6 are correct
8 0
3 years ago
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You start at (6, 8). You move right 4 units and left 2 units. Where do you end?
Sati [7]

Answer:

8,6

Step-by-step explanation:

7 0
3 years ago
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−2(x+1)=x−3x−2 No solution, one solution, or infinite solutions
VLD [36.1K]

Answer:

x=3

Step-by-step explanation:

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3 0
3 years ago
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Find dy/dx any one <br>x=acost , y=asint​
dangina [55]

Answer:

x=a \cos t \implies \dfrac{dx}{dt}=-a \sin t

y= a \sin t \implies \dfrac{dy}{dt}=a \cos t

Using the chain rule:

\begin{aligned}\implies \dfrac{dy}{dx} & =\dfrac{dy}{dt} \times \dfrac{dt}{dx}\\\\& = a \cos t \times \dfrac{1}{-a \sin t}\\\\& = \dfrac{a \cos t}{-a \sin t}\\\\& = - \dfrac{\cos t}{\sin t}\\\\& = - \cot t\end{aligned}

8 0
2 years ago
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