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3 years ago

I REALLY NEED HELP.

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

I'm just saying, but I think that a) is supposed to be 4, since there are 4 points having 0 as x or y.

(By the way thanks for adding the attachment this time!)

Verdich [7]3 years ago

4 0

A) the zeros are -2,1,and 3
b) (x+2)(x-1)(x-3)
c) x^3−2x^2−5x+6

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Determine the temperature of 2.6 moles of gas contained in a 5.00-L vessel at a pressure of 1.2atm.

strojnjashka [21]

Answer:

28.108 K.

Step-by-step explanation:

Given: Pressure (P)= 1.2atm

Number of moles (n)= 2.6 moles

Volume (V)= 5.00-L

Now finding the temperature (T).

Formula; T= $\frac{P\times V}{n\times R}$

R is a constant factor which makes other factors work together.

There is a numerical value for R which we use is $0.0821 \times \frac{L.atm}{mole.K}$

∴ Temperature (T)= $\frac{1.2\times 5}{2.6\times 0.0821 \frac{L.atm}{mol.K} }$

⇒ Temperature (T)= $\frac{6}{0.21346} = 28.1083\ K$

∴ Temperature is 28.108 K

8 0

3 years ago

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

3 years ago

The national assessment of educational progress (naep) gave a test of basic arithmetic and the ability to apply it in everyday l

HACTEHA [7]

<span>Ans : a) What is the standard deviation of this sampling distribution? Ď /âšn = 60/âš840 =2.0702 b) 1 standard deviation of the mean = (1) 2.07 = 2.07 c) 272+/- 1(2.07) (269.93, 274.07)</span>

3 0

3 years ago

If billy can read 2 pages in 6 minutes, how many pages can he read in 24 minutes?

german

Answer:

8 mins

Step-by-step explanation:

First you see how many mins he can read on 1 page than you divided the number by 24 to get your answer.

8 0

3 years ago

2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe

k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

$N=(25+60)+(40+60) - 60\\N= 125$

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

$P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%$

3 0

3 years ago