Answer:
x = 7
y = 0
Step-by-step explanation:
→To solve this, you can use the elimination method. To do this, you must have one set of variables that can cancel each other out. In the problem given, we already have positive 4x and -4x, making them cancel out:
4x + 9y = 28
-4x - y = -28
__________
8y = 0
y = 0
<u>→Plug in 0 for y, into an equation:</u>
-4x - 0 = -28
-4x = -28
x = 7
Given the equation:
Applying the exponent laws:
![\begin{gathered} \sqrt[3]{((5x-16)^3-4)^3}=\sqrt[3]{216000} \\ (5x-16)^3-4=60 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B3%5D%7B%28%285x-16%29%5E3-4%29%5E3%7D%3D%5Csqrt%5B3%5D%7B216000%7D%20%5C%5C%20%285x-16%29%5E3-4%3D60%20%5Cend%7Bgathered%7D)
Simplify:
Applying the exponent laws:
![\begin{gathered} \sqrt[3]{(5x-16)^3}=\sqrt[3]{64} \\ Simplify \\ 5x-16=4 \\ 5x-16+16=4+16 \\ 5x=20 \\ \frac{5x}{5}=\frac{20}{5} \\ x=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B3%5D%7B%285x-16%29%5E3%7D%3D%5Csqrt%5B3%5D%7B64%7D%20%5C%5C%20Simplify%20%5C%5C%205x-16%3D4%20%5C%5C%205x-16%2B16%3D4%2B16%20%5C%5C%205x%3D20%20%5C%5C%20%5Cfrac%7B5x%7D%7B5%7D%3D%5Cfrac%7B20%7D%7B5%7D%20%5C%5C%20x%3D4%20%5Cend%7Bgathered%7D)
Answer: x = 4
To solve the give logarithm we proceed as follows;
log7(3x^3+x)-log7(x)=2
this can be written as:
log7[(3x^3+x)/(x)]=2
but;
log7(49)=2
thus;
log7(3x^3+x)/x=log7(49)
hence canceling log7 we get:
(3x^3+x)/x=49
This can be simplified further to get:
3x^2+1=49
3x^2=49-1
3x^2=48
x^2=48/3
x^2=16
getting the square root of both sides we get:
x=4
the answer is x=4
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Answer:
Multiple choice?
Step-by-step explanation:
