A = P(1+r/12)^12t, where A = amount after two years, P = Initial amount = $1000, r =apr = 4.2% = 0.042, t = period = 2 years
Then,
A = 1000 (1+0.042/12)^12*2 = $1087.47
It’s the third one.
144. 6 x 6 = 36
36 x 8 = 288
288 divided by 2 ( divide by half the dotted line)
answer : 144
The values of BMW after 2 years and 4 years according to the EXPONENTIAL FUNCTION are $33,462 and $20,358.28
Using the parameters given, we define an decreasing exponential function :

Where,
= initial amount ; r = Rate ; t = time ; A = final amount
Value after 2 years :
t = 2
A = 55000(1 - 0.22)²
A = 55000(0.78)²
A = $33,462
Value after 4 years :
t = 4
A = 55000(1 - 0.22)^4
A = 55000(0.78)^4
A = $20,358.28
Therefore, the value of BMW after 2 years and 4 years $33,462 and $20,358.28 respectively.
Learn more :
brainly.com/question/14355665
I think it’s not equal because if you took (1)(2)(3). You would need to multiply them not add them. It would be 9 = (1,2,3)
A)
![\bf 1990-1910=80\leftarrow t \\\\\\ P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}} \\\\\\ P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}](https://tex.z-dn.net/?f=%5Cbf%201990-1910%3D80%5Cleftarrow%20t%0A%5C%5C%5C%5C%5C%5C%0AP%28t%29%3D8000%282%29%5E%7B-%5Cfrac%7Bt%7D%7B29%7D%7D%5Cimplies%20P%2880%29%3D8000%282%29%5E%7B-%5Cfrac%7B80%7D%7B29%7D%7D%0A%5C%5C%5C%5C%5C%5C%0AP%2880%29%3D8000%5Ccdot%20%5Ccfrac%7B1%7D%7B2%5E%7B%5Cfrac%7B80%7D%7B29%7D%7D%7D%5Cimplies%20P%2880%29%3D%5Ccfrac%7B8000%7D%7B%5Csqrt%5B29%5D%7B2%5E%7B80%7D%7D%7D)
and surely you know how much that is.
b)

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.